At the _______________ point, the particles in an object have not kinetic energy

2. If you were trying to determine if cars in your neighborhood were travelling at or below the posted speed limit, how would yo

Varvara68 [4.7K]

Speed is defined as the distance over time. So in measuring the speed of a car, the most manual thing that we can do besides using a speedometer is to measure a certain distance then measure the time at which the car passes that distance then divide the distance over the time. Then determine the speed limit.

4 0

3 years ago

The maximum tension the wire can withstand without breaking is 300 N . A 0.800 kg projectile traveling horizontally hits and emb

topjm [15]

Answer:

Let's investigate the case where the cable breaks.

Conservation of angular momentum can be used to find the speed.

$\vec{L}_1 = \vec{L}_2\\\vec{L}_1 = m\vec{v_0} \\\vec{L}_2 = I\vec{\omega}\\$

The projectile embeds itself to the ball, so they can be treated as a combined object. The moment of inertia of the combined object is equal to the sum of the moment of inertia of both objects.

$I = I_{projectile} + I_{ball}\\I = mr^2 + mr^2\\I = 2mr^2$

where r is the length of the cable.

After the collision, the ball and the projectile makes a circular motion because of the cable. So, the force (tension) in circular motion is

$F = \frac{mv^2}{r}$

The relation between linear velocity and the angular velocity is

$v = \omega r$

So,

$F = \frac{m(\omega r)^2}{r} = m\omega^2 r = 300\\mv_0r =I\omega\\\\\omega = mv_0r/I\\300 = m(\frac{mv_0r}{I})^2r = m(\frac{mv_0r}{2mr^2})^2r = m(\frac{v_0}{2r})^2r = \frac{mv_0^2r}{4r^2} = \frac{mv_0^2}{4r}\\300 = \frac{0.8v_0^2}{4r}\\1500 = v_0^2/r\\v_0 = \sqrt{1500r}$

As can be seen, the maximum velocity for the projectile without breaking the cable is $\sqrt{1500r}$ , where r is the length of the cable.

6 0

3 years ago

The gravitational force of a star on an orbiting planet 1 is f1. planet 2, which is four times as massive as planet 1 and orbits

Keith_Richards [23]

Answer: F=GMm/r^2 where G is the newtonian grav cst, M the mass of the star, m the mass of the planet, and r the planet-star distance F1=GMm1/r1^2 F2=GMm2/r^2 F2/F1 = [GMm2/r2^2]/[GMm1/r1^2] F2/F1=(m2/m1)(r1/r2)^2 = (2)(1/2)^2 = 1/2 because m2/m1=2 and r2/r1=2

8 0

3 years ago

What type of front occurs when cold air and warm air are next to each other but are at a standstill

Korvikt [17]

Answer:

A stationary front.

(Hope this helped! c:)

5 0

3 years ago

Thomson's cathode ray beam bent towards the positively charged plate. With this information, he was able to conclude

andre [41]

I believe the correct answer from the choices listed above is the second option. With this information, he was able to conclude that the beam was negatively charged. His cathode ray tube experiments led to a very important scientific discovery, the electron. Hope this answers the question.

8 0

3 years ago

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