Answer:
the lowest common multiple is 60
Step-by-step explanation:
The multiples of 12 are : 12, 24, 36, 48, 60, 72, 84,
The multiples of 15 are : 15, 30, 45, 60, 75, 90, ....
60 is a common multiple (a multiple of both 12 and 15), and there are no lower common multiples.
Therefore, the lowest common multiple of 12 and 15 is 60.
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
Unit rate is the amount it costs for 1.
Divide total cost by number bought:
25/4 = 6.25
Unit price = $6.25 per ticket
Answer:
(x, y) = (-1, 9)
Step-by-step explanation:
A graphical solution can be quick and easy. It shows the solution to be ...
(x, y) = (-1, 9)
__
Another suitable method is Cramer's rule. It makes use of a particular pattern of sum of products of coefficients and constants. The denominator in each case is the same sum of products.
x = (5(-29)-(-3)(31))/(5(2)-(-3)(14)) = -52/52 = -1
y = (31(2)-(-29)(14))/52 = 468/52 = 9
