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labwork [276]
3 years ago
13

The area of the trapezoid is 108 in2. What is the height of the trapezoid?

Mathematics
2 answers:
arsen [322]3 years ago
6 0
Area for a trapezoid is A= a+b/2 times h  (a and b are the bases which are 8 and 10 

so 108=8+10/2 x h 8+10 divided by 2 equals 9 so now we have 108=9 x h

now we must divide both sides by 9 to solve for the height 108/9 equals 12 so the height of the trapezoid is 12
dezoksy [38]3 years ago
5 0

The area of the trapezoid is given by the formula A= (a+b)/ 2 * h

in this question a= 8, b= 10, A= 108 inches², and h is what we have to find, substitute what we have got into the formula and you will have:

108= (8+10) /2 *h

108= 9 *h

h= 108/9

h= 12 inches



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Answer:

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ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

\overrightarrow {PQ}==

\overrightarrow {PR}==

The nonzero vector orthogonal to the plane through the points P,Q, and R is

\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}

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Expand along row 1.

\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}

\overrightarrow n=i(-9)-j(8)+k(2)

\overrightarrow n=-9i-8j+2k

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Answer:

One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.


Step-by-step explanation:


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