(2x² - 5) - (3x² + 4).
Pretend that there is a -1 in front of :(3x² + 4).
(2x^2-5)-1(3x^2+4)
2x^2-5-3x^-4
2x^2-3x^2-5-4
=-x^2-9
Answer: -x^2-9

Micah did not explain the last step correctly. You cannot cross out a term from the numerator and denominator unless it is a factor. In other words, x² needed to be multiplied and not added in order to cross it out.
Answer:
parallelogram
Step-by-step explanation:
The answer is: 10
Hope this helps! (:
Answer:
x =3 sqrt(3)
Step-by-step explanation:
cos theta = adj/ hyp
cos 60 = x/ 6 sqrt(3)
Multiply each side by 6 sqrt(3)
6 sqrt(3) cos 60 = x/6 sqrt(3)/ 6 sqrt(3)
x =cos 60 * 6 sqrt(3)
x =3 sqrt(3)