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Vinil7 [7]
3 years ago
15

. Find the 20th term of the arithmetic sequence 15, 9, 3, -3

Mathematics
1 answer:
vova2212 [387]3 years ago
3 0

Answer:

a20 = -99

Step-by-step explanation:

hello :

the nth term in this  arithmetic sequence is : an = a1 + (n -1 )d

a1 = 15   a2 = 9       d = a2-a1 = 9-15 = -6  ( common difrence)

an = 15 + (n -1 )(-6)

an = 15+6-6n

an = -6n+21

the 20th term when n = 20 :  a20 = -6(20)+21 = -99

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Step-by-step explanation:

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Please help me and If your answer is wrong or not appropreat I will report it
arsen [322]

Answer:

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Step-by-step explanation:

Simplify the following:

(-2 x^3 y^7)^2 (3 x^2 y^2)^5

Multiply each exponent in -2 x^3 y^7 by 2:

(-2)^2 x^(2×3) y^(2×7) (3 x^2 y^2)^5

2×7 = 14:

(-2)^2 x^(2×3) y^14 (3 x^2 y^2)^5

2×3 = 6:

(-2)^2 x^6 y^14 (3 x^2 y^2)^5

(-2)^2 = 4:

4 x^6 y^14 (3 x^2 y^2)^5

Multiply each exponent in 3 x^2 y^2 by 5:

4 x^6 y^14×3^5 x^(5×2) y^(5×2)

5×2 = 10:

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5×2 = 10:

4×3^5 x^6 y^14 x^10 y^10

3^5 = 3×3^4 = 3 (3^2)^2:

4×3 (3^2)^2 x^6 y^14 x^10 y^10

3^2 = 9:

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9^2 = 81:

4×3×81 x^6 y^14 x^10 y^10

3×81 = 243:

4×243 x^6 y^14 x^10 y^10

4 x^6 y^14×243 x^10 y^10 = 4 x^(6 + 10) y^(14 + 10)×243:

4×243 x^(6 + 10) y^(14 + 10)

14 + 10 = 24:

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6 + 10 = 16:

4×243 x^16 y^24

4×243 = 972:

Answer: 972 x^16 y^24

8 0
2 years ago
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Step-by-step explanation:

3 0
3 years ago
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To find this, we simply have to put 0 in for x, as this is when there has been no time (at launch)

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7 0
3 years ago
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