Question

c.) Compute the estimated theoretical maximum delay that can be generated if a microcontroller runs at 48Mhz and it takes three instruction to execute a single iteration of the following delay loop for (x=0;x

Answer 1

Answer:

 

T1 = 1/12  x 48 MHz = 4 MHz

Timer’s clock period:

The time delay of one machine cycle is given below. We use this to generate the delay.

T2= 1/ 4000000= 0.25 µ sec

For delay of 10 ms:

1. Firstly divide the desired time delay value (10 ms) by the timer clock period.

N=  1 / 0.25µs

N= 10 ms / 0.25µsec

N=40000

2. Subtract the value of N from the maximum number of counts possible for 16 bit timer i.e. 2^16 = 65536.

M=65536-N

M=65536-40,000

M= 25536

Explanation:

Clock source: