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3 years ago

If a car was cruising down the highway at 80 km/hr, how fast would the people inside the car be traveling?

2 answers:

6 0

Because the people in the car are attached to the vehicle, the people inside the vehicle are going the same speed as the vehicle.

Hope this helps! :)

luda_lava [24]3 years ago

3 0

The people inside the car are at rest (speed = zero) relative to the car, moving 80 km/hr relative to the pavement, and slightly slightly less relative to a worm slithering on the road in the same direction as the car.

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6. Explain Why does coating surfaces with oil reduce friction<br> between the surfaces?

Akimi4 [234]

Answer:

hope this helps

Explanation:

Coating surfaces with oil reduce friction between the surfaces because it is like when lubricating a machine, it makes it run or it makes it become smoother.

7 0

3 years ago

Read 2 more answers

A ball was rolling downhill at 2 m/s. After 5s, it was rolling at 90 m/s. What is its acceleration?

olga55 [171]

Answer:

17.6 m/s²

Explanation:

Given:

$v_{f}$ = 90 m/s (final velocity)

$v_{i}$ = 2 m/s (initial velocity)

Δt = 5s (change in time)

The formula for acceleration is:

$a_{avg}$ = Δv / Δt

We can find Δv by doing

Δv = $v_{f}$ - $v_{i}$

Replace the values

Δv = 90m/s - 2m/s

Δv= 88m/s

Using the equation from earlier, we can find the acceleration by dividing the average velocity by time.

$a_{avg}$ = Δv / Δt

$a_{avg}$ = $\frac{88m/s}{5/s}$

acceleration = 17.6 $m/s^{2}$

4 0

3 years ago

If the moon is rising at midnight, the phase of the moon must be

Nadya [2.5K]

The phase is called 3rd quarter.

Hope this helps:)

7 0

3 years ago

What is the electrical force between q2 and q3? recall that k = 8.99 × 109 n•meters squared over coulombs squared.. 1.0 × 1011 n

max2010maxim [7]

The magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.

<h3>What is the magnitude of electrical forces between two charges?</h3>

The magnitude of the electrical force between two charges refers to the attractive or repulsive forces that exists between two charges separated by a given distance in an electric field.

The magnitude of the electrical force, F between the two charges q2 and q3 is given be my the formula below

$F = \frac{K \times q_2 \times q_3}{d^{2}}$

Therefore, the magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.

Learn more about electrical force at: brainly.com/question/17692887

#SPJ4

6 0

2 years ago

An arrow is projected by a bow vertically up with a velocity of 40 m/s, and reaches a target in 3 s. What is the velocity of the

Fittoniya [83]

Answer:

Explanation:

Step one:

given data

initial velocity u= 40m/s

time taken t=3seconds

final velocity v=?

Step two:

applying the first equation of motion

v=u-gt--- (the -ve sign implies that the arrow is against gravity)

assume g=9.81m/s^2

v=40-9.81*3

v=40-29.43

v=10.57m/s

Step three:

how high the target is located

applying

s=ut-1/2gt^2

s=40*3-1/2(9.81)*3^2

s=120-88.29/2

s=120-44.145

s=75.86m

6 0

3 years ago