A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.
<h3>What is a decomposition reaction?</h3>
A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.
- Step 1: Write the balanced equation for the decomposition of KHCO₃.
2 KHCO₃(s) → K₂CO₃(s) + CO₂(g) + H₂O(l)
The mass loss of 0.275 g is due to the gaseous CO₂ that escapes the sample.
- Step 2: Calculate the mass of KHCO₃ that formed 0.275 g of CO₂.
In the balanced equation, the mass ratio of KHCO₃ to CO₂ is 200.24:44.01.
0.275 g CO₂ × 200.24 g KHCO₃/44.01 g CO₂ = 1.25 g KHCO₃
- Step 3: Calculate the mass percentage of KHCO₃ in the sample.
There are 1.25 g of KHCO₃ in the 1.775 g sample.
%KHCO₃ = 1.25 g/1.775 g × 100% = 70.4%
A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.
Learn more about decomposition reactions here: brainly.com/question/14219426
Answer:
V = 96.61 L
Explanation:
Given data:
Number of moles = 4.0 mol
Pressure = 780 torr (780/760 = 1.03 atm)
Temperature = 30°C
Volume of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
30+273 = 303 K
1.03 atm × V = 4.0 mol × 0.0821 atm.L/ mol.K × 303 K
V = 99.505 atm.L / 1.03 atm
V = 96.61 L
Answer:
0.003088 moles of hydrogen gas were formed .
Explanation:
Pressure at which hydrogen gas is collected at 20°C = 768.0 Torr
Vapor pressure of water at 20°C = 17.5 Torr
Total pressure = Vapor pressure of water + Partial pressure of hydrogen gas
Partial pressure of hydrogen gas:
Total pressure - Vapor pressure of water
= 768.0 Torr - 17.5 Torr = 750.5 Torr = 0.987 atm
(1 Torr = 0.001315 atm)
Pressure of hydrogen gas =P = 0.986 atm
Temperature at which gas was collected ,T= 20°C = 293.15 K
Volume of the gas ,V= 75.3 mL = 0.0753 L
Moles of hydrogen gas = n
PV=nRT (An ideal gas equation)
0.003088 moles of hydrogen gas were formed .
The initial temperature of the metal = 35 °C
<h3>Further explanation</h3>
Heat can be formulated :
Q = m . c . ΔT
Q = heat, J
c = specific heat, J/g C
ΔT = temperature, °C
m = 20 g
c = 5 J/(g°C)
Q = 500 J
T₁ = 40 C
the initial temperature :
