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lara [203]
3 years ago
14

Which element can expand its valence shell to accommodate more than eight electrons? which element can expand its valence shell

to accommodate more than eight electrons? o he n br?
Chemistry
2 answers:
amm18123 years ago
4 0

Answer:

Br can expand its valence shell to accommodate more than eight electrons.

Explanation:

In a bond, elements tends to accommodate their valence electrons to reach the configuration of a noble gas (The Octet rule), so they try to complete their valence shell with 8 electrons, and they can do that only if they use the <u>orbitals s</u> (may contain only 2 electrons) <u>and p</u> (may contain only 6 electrons).

Sometimes, there are elements that need to share more than 8 valence electrons to use all the available electrons, but this is possible only if the atom has <u>orbitals d</u> (may contain 10 electrons) <u>or f</u> (may contain 14 electrons).

That's why <u>only the elements that has a number 3 of period or more can expand its valence shell</u>, because level 3 atoms has a <em>d subshell</em>.

In this case, He atom is in period number 1, N atom is in period number 2 and Br atom is in period number 3, that's why Br atom can expand its valence shell, and He and N atoms can't.

Anvisha [2.4K]3 years ago
3 0
<span>According to octet rule,  atoms with an atomic number less than 20 tend to combine  with other atom such that both of these atoms have eight electrons in their valence shells, which gives them the same electronic configuration as that of noble gas.

However, there are few compound that donot obey octel rule. Among the elements mentioned above i.e. oxygen and helium obeys octet rule.

In case of nitrogen, oxide of nitrogen (like NO and NO2) have incomplete octet. 

While there are few compounds of Br wherein Br has expanded octet. For example, in BrF5, Br has 12 electrons in valence shell. </span>
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Cellular respiration role during water cycle
maks197457 [2]

Answer:

Explanation:

Our breath being absorbed by the atmosphere and dumped back down in the form of rain or snow is one of them. Respiration is the most important metabolic process for animals that can't make their own energy. It allows organisms to gather oxygen from the air in exchange for carbon dioxide and water vapor .

6 0
3 years ago
mixture of N 2 And H2 Gases weighs 13.22 g and occupies a volume of 24.62 L at 300 K and 1.00 atm.Calculate the mass percent of
anygoal [31]

<u>Answer:</u> The mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of the gaseous mixture = 1.00 atm

V = Volume of the gaseous mixture = 24.62 L

n = number of moles of the gaseous mixture = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gaseous mixture = 300 K

Putting values in above equation, we get:

1.00atm\times 24.62L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\n_{mix}=\frac{1.00\times 24.62}{0.0821\times 300}=0.9996mol

We are given:

Total mass of the mixture = 13.22 grams

Let the mass of nitrogen gas be 'x' grams and that of hydrogen gas be '(13.22 - x)' grams

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

<u>For nitrogen gas:</u>

Molar mass of nitrogen gas = 28 g/mol

\text{Moles of nitrogen gas}=\frac{x}{28}mol

<u>For hydrogen gas:</u>

Molar mass of hydrogen gas = 2 g/mol

\text{Moles of hydrogen gas}=\frac{(13.22-x)}{2}mol

Equating the moles of the individual gases to the moles of mixture:

0.9996=\frac{x}{28}+\frac{(13.22-x)}{2}\\\\x=12.084g

To calculate the mass percentage of substance in mixture we use the equation:

\text{Mass percent of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100

Mass of the mixture = 13.22 g

  • <u>For nitrogen gas:</u>

Mass of nitrogen gas = x = 12.084 g

Putting values in above equation, we get:

\text{Mass percent of nitrogen gas}=\frac{12.084g}{13.22g}\times 100=91.41\%

  • <u>For hydrogen gas:</u>

Mass of hydrogen gas = (13.22 - x) = (13.22 - 12.084) g = 1.136 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen gas}=\frac{1.136g}{13.22g}\times 100=8.59\%

Hence, the mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

5 0
3 years ago
Consider these reactions:
Virty [35]

511.2 grams of chlorine gas consumed (with excess H-) when

1,342.0 kJ of energy is released from the system.

<h3></h3><h3>What is an exothermic reaction?</h3>

In thermochemistry, an exothermic reaction is a "reaction for which the overall standard enthalpy change ΔH⚬ is negative."

Given that 1 mole of chlorine releases -184.6 energy.

Then, we have to find the number of moles of chlorine when 1,342.0 kJ of energy is released from the system.

So, calculating number of moles of chlorine.

Moles = \frac{-1,342.0 \;kJ}{-184.6\;kJ}

Moles = 7.2 mole

Now, calculating number mass of chlorine.

\rm Moles=\rm\frac{Mass}{Molar \;mass}

Mass =  7.2 mole x 71 g/mole

Mass = 511.2 gram

Learn more about exothermic reaction here:

brainly.com/question/10373907

#SPJ1

3 0
2 years ago
How many moles of carbon in 6.64 moles of CCl2 F
Bad White [126]

Answer: 6.64 moles of carbon.

Explanation:

Given data:

Number  of moles of C = ?

Number of moles of CCl₂F₂ = 6.64 mol

Solution:

In one mole of CCl₂F₂ there is one mole of carbon two moles of chlorine and two moles of fluorine are present.

In 6.6 moles of CCl₂F₂ :

Moles of carbon = 6.64 × 1 = 6.64 moles of carbon.

Moles of chlorine = 6.64× 2 = 13.28 moles of chlorine

Moles of fluorine = 6.64× 2 = 13.28 moles of fluorine

Read more on Brainly.com - brainly.com/question/15602143#readmore

3 0
3 years ago
How is Hess's law used to measure enthalpy of a desired reaction?
Morgarella [4.7K]

Answer:

D

Explanation:

I hope this is correct

6 0
3 years ago
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