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lara [203]
3 years ago
14

Which element can expand its valence shell to accommodate more than eight electrons? which element can expand its valence shell

to accommodate more than eight electrons? o he n br?
Chemistry
2 answers:
amm18123 years ago
4 0

Answer:

Br can expand its valence shell to accommodate more than eight electrons.

Explanation:

In a bond, elements tends to accommodate their valence electrons to reach the configuration of a noble gas (The Octet rule), so they try to complete their valence shell with 8 electrons, and they can do that only if they use the <u>orbitals s</u> (may contain only 2 electrons) <u>and p</u> (may contain only 6 electrons).

Sometimes, there are elements that need to share more than 8 valence electrons to use all the available electrons, but this is possible only if the atom has <u>orbitals d</u> (may contain 10 electrons) <u>or f</u> (may contain 14 electrons).

That's why <u>only the elements that has a number 3 of period or more can expand its valence shell</u>, because level 3 atoms has a <em>d subshell</em>.

In this case, He atom is in period number 1, N atom is in period number 2 and Br atom is in period number 3, that's why Br atom can expand its valence shell, and He and N atoms can't.

Anvisha [2.4K]3 years ago
3 0
<span>According to octet rule,  atoms with an atomic number less than 20 tend to combine  with other atom such that both of these atoms have eight electrons in their valence shells, which gives them the same electronic configuration as that of noble gas.

However, there are few compound that donot obey octel rule. Among the elements mentioned above i.e. oxygen and helium obeys octet rule.

In case of nitrogen, oxide of nitrogen (like NO and NO2) have incomplete octet. 

While there are few compounds of Br wherein Br has expanded octet. For example, in BrF5, Br has 12 electrons in valence shell. </span>
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An ideal gas in a sealed container has an initial volume of 2.80 L. At constant pressure, it is cooled to 18.00 °C, where its
Aleks04 [339]

Answer:

T_1=-91.18\°C

Explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

\frac{T_1}{V_1}= \frac{T_2}{V_2}

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C

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6 0
3 years ago
Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:
lubasha [3.4K]

Solution :

a). $SO_3$

  This compound is known as sulfur trioxide.

  The molecular shape of sulfur trioxide is trigonal planer.

   And the bond angle is 120°.

b). $N_2O$

   This compound is known as Nitrous oxide. Here, nitrogen is in the center.     There is no lone pair around the nitrogen atom and it forms two sigma bonds with the other two atoms.

 It is linear in shape.

  The bond angle between them is 180°.

c). $CH_2Cl_{2}$

  This compound is known as the Dichloromethane.

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6 0
3 years ago
The shape of the sulfur dioxide molecule, where sulfur is the central atom is
fgiga [73]

Answer:

bent

Explanation:

The molecular formula of sulfur dioxide is written as SO₂

The molecular geometry of sulfur dioxide can be determined using the Lewis structure.

The Lewis structure shows the distribution of electrons around the atoms of a given compound such as sulfur dioxide (SO₂).

In this compound, sulfur is the central atom with 6 valence electrons.

The sulfur is bonded covalently with two oxygen atoms, each with 6 valence electrons. Oxygen contributes 2 lone pairs while sulfur which is the central atom contributes 1 lone pair of electrons in the bond.

The bond angle between the two oxygen atoms and the central sulfur atom is approximately 120⁰, as a result of the bent shape of the molecular structure.

7 0
3 years ago
In the reaction Zn H 2SO 4→ ZNSO4 + H2, which, if any element is oxidized
Sedbober [7]

Answer:

I hope this answer is correct

Explanation:

This is an oxidation-reduction (redox) reaction:

Zn0 - 2 e- → ZnII (oxidation)

2 HI + 2 e- → 2 H0 (reduction)

Zn is a reducing agent, H2SO4 is an oxidizing agent.

Reactants:

Zn

Names: Zinc source: wikidata, accessed: 2019-09-07, Zinc powder (pyrophoric) source: ICSC, accessed: 2019-09-04, Zn source: wikidata, accessed: 2019-09-07

Appearance: Grey-to-blue powder source: ICSC, accessed: 2019-09-04

H2SO4 – Sulfuric acid source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-07source: NIOSH NPG, accessed: 2019-09-02

Other names: Oil of vitriol source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-07source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Sulfuric acid, concentrated (> 51% and < 100%) source: ICSC, accessed: 2019-09-04, H2SO4 source: wikidata, accessed: 2019-09-07

Appearance: Clear, colorless liquid source: wikipedia, accessed: 2019-09-27; Odourless colourless oily hygroscopic liquid source: ICSC, accessed: 2019-09-04; Colorless to dark-brown, oily, odorless liquid. [Note: Pure compound is a solid below 51°F. Often used in an aqueous solution.] source: NIOSH NPG, accessed: 2019-09-02

Products:

ZnSO4 – Zinc sulfate source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04

Other names: White vitriol source: wikipedia, accessed: 2019-09-27, Goslarite source: wikipedia, accessed: 2019-09-27, Zinc sulfate (1:1) source: wikidata, accessed: 2019-09-02

Appearance: White powder source: wikipedia, accessed: 2019-09-27; Colourless hygroscopic crystals source: ICSC, accessed: 2019-09-04

H2

Names: Dihydrogen source: wikidata, accessed: 2019-09-07, Hydrogen source: ICSC, accessed: 2019-09-04source: wikidata, accessed: 2019-09-07, H2 source: wikidata, accessed: 2019-09-07

7 0
3 years ago
Which of the following describes water's ability to dissolve substances?
kicyunya [14]
Water is polar and dissolves polar substances
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3 years ago
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