Answer:
Longer than 27.7 minutes.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
The slowest quarter of customers will require longer than how many minutes (to the nearest tenth) for a simple haircut?
Longer than the 100 - 25 = 75th percentile of times, which is X when Z has a pvalue of 0.75. So X when Z = 0.675. So
So
Longer than 27.7 minutes.
9514 1404 393
Answer:
30 small chairs and 24 large chairs
Step-by-step explanation:
Let x and y represent the numbers of small chairs and large chairs built in a day. Then the relations for using available time are ...
20x +50y = 30×60
60x +90y = 66×60
Removing common factors, these can be written in standard form as ...
2x +5y = 180
2x +3y = 132
Subtracting the second equation from the first gives ...
2y = 48
y = 24 . . . . . divide by 2
Using the first equation to find x, we have ...
2x +5(24) = 180
2x = 60 . . . . . . . . . . subtract 120
x = 30 . . . . . . . . divide by 2
The company can build 30 small chairs and 24 large chairs in a day.
Answer:
-26.1 , -0.01 , 12% , 1/4 , 3-4
Step-by-step explanation:
We know that Bob and Caitlyn are playing a trading-card game. Between them, they have 81 cards. <span>Bob has 7 fewer cards than Caitlyn. Since Bob has 7 cards fewer them Caitlyn we have to divide by 2 and subtract 7.
81 / 2 = 40 [rounded]
40 - 7 = cards Bob has
= 33 cards bob has
</span>
Answer:
"The mean is the average of the numbers: a calculated "central" value of a set of numbers. To calculate it: add up all the numbers, then divide by how many numbers there are." -- Math is Fun
