All categories

2 years ago

So it's got like money before and after and it has indepent and dependent variable

Mathematics

1 answer:

alex41 [277]2 years ago

7 0

Answer:

The dependent variable is the amount of money you earn because the amount of money you earn depends on how many chores you do.

You might be interested in

Which event took place during the Copernican revolution, when most people started to believe in a heliocentric model of the sola

sladkih [1.3K]

Answer: B: copernicus....

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

6 0

4 years ago

Please help ASAP! X= A) 4 B) 7 C) 9

melisa1 [442]

Answer:

C) x = 9

Step-by-step explanation:

When two segments intersect in a circle like so, the product of the two parts of one segment will be equal to the product of the two parts of the other segment.

So, 3 * 6 = x * 2

Multiply: 18 = x * 2

Divide: x = 9

8 0

4 years ago

Read 2 more answers

12. If you flip a dime 50 times:

nata0808 [166]

Answer: 25 heads 25 tails

Step-by-step explanation: you would have a 50/50 chance to get heads or tails so sence there are 2 sides you would get 25 heads and 25 tails

4 0

3 years ago

Read 2 more answers

7.)

I am Lyosha [343]

Answer:

The final temperature for the day was -16 degrees.

Step-by-step explanation:

6-12= -6

-6-10= -16

8 0

3 years ago

So it's got like money before and after and it has indepent and dependent variable ​

So it's got like money before and after and it has indepent and dependent variable