Answer:
15.5 km
Explanation:
1.55 x 10^4 m means 1.55 x 10000 = 15,500 m
1 km = 1000 meters
To convert to km we divide by 1000
So 15,500/1000
= 15.5 km
Answer:
The answer to your question is below
Explanation:
a)
Number of atoms = ?
moles of Fe = 4.75
-Use proportions to solve this problem
1 mol of Fe --------------------- 6.023 x 10²³ atoms
4.75 moles --------------------- x
x = (4.75 x 6.023 x 10²³) / 1
x = 2.86 x 10²⁴ / 1
Number of atoms = 2.86 x 10²⁴
b)
Number of moles = ?
moles of 1.058 moles of H₂O
I think this question is incorrect, maybe you wish to know the number of atoms or grams of H₂O.
c)
Number of atoms = ?
moles of Fe = 0.759
1 mol of Fe ------------------ 6.023 x 10²³ atoms
0.759 moles --------------- x
x = (0.759 x 6.023 x 10²³) / 1
x = 4.57 x 10²³ / 1
Number of atoms of Fe = 4.57 x 10²³ atoms
d)
Number of molecules = ?
moles of H₂O = 3.5 moles
1 mol of H₂O ------------------ 6.023 x 10²³ molecules
3.5 moles ------------------ x
x = (3.5 x 6.023 x 10²³) / 1
x = 2.11 x 10²⁴ molecules
Number of molecules = 2.11 x 10²⁴
Answer:
H2O
Explanation:
PLS MARK ME TO THE BRAINLIST
Rf values may vary. Rf values vary depending on the material and solvent. The solvent that is used will alter the Rf value.
Rf values are typically higher for low polarity chemicals compared to higher polarity ones. Generally speaking, as polarity of a compound increases, so does its adsorptivity (i.e. the more polar the compound then the stronger it binds to the adsorbent). Solvents get more eluting as they become more polar.
The greater the compound's polarity, the more readily it will bind to the adsorbent, the closer it will come to the baseline, and the lower its Rf value. Many scientists use normal-phase flash chromatography with dichloromethane and methanol as the mobile phase to purify polar organic molecules. Due to methanol's high polarity and protic chemistry, it can frequently be difficult to optimize this solvent system.
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The question is as follows: What is the% m / m of a solution in which 22 g of solute are dissolved in 44 g of solvent?
Answer: The% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.
Explanation:
Given: Mass of solute = 22 g
Mass of solvent = 44 g
The percentage m/m is calculated using the following formula.
Substitute the values into above formula as follows.
Thus, we can conclude that the% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.
