In nuclear physics and nuclear chemistry, nuclearfission<span> is either a nuclear </span>reaction<span> or a radioactive decay process in which the nucleus of an atom splits into smaller parts (lighter nuclei).</span>
Strong electron withdrawing groups prevents Friedel Crafts reaction because when a withdrawing group attracts the electrons decrease the availability of the electronic pair and the enough electronic density of it in order to make possible the aromatic electrophilic substitution.
Strong electron donating groups like NH2 doesn’t undergo Friedel Crafts reaction because NH2 is a Lewis base that means an electron donor. Due to Friedel Crafts reaction is an acid base reaction, the AlCl3 will be attacked by the lone pair available from NH2 producing a salt. The same occurs with phenol because the lone pair of electrons available in the OH group so Friedels Crafts doesn’t undergo with benzene attached to the strong electron donating groups NH2 or OH.
Phosphorus - P - Protons = 15, Electrons = 15, Neutrons = 16 - Non-Metal
Lithium - Li - Protons = 3, Electrons = 3, Neutrons = 4 - Metal
Nitrogen - N - Protons = 7, Electrons = 7, Neutrons = 7 - Non-Metal
Copper - Cu - Protons = 29, Electrons = 29, Neutrons = 34 - Metal
Neon - Ne - Protons = 10, Electrons = 10, Neutrons = 10 - Non-Metal
sorry i don’t know about the other questions but i thought i could help with the table!
Additional Info:
number of protons = atomic number
number of electrons = atomic number
number of neutrons = mass number - atomic number
<u>Answer:</u>
a. Oxidising agent: Cl₂
b. Reducing agent: NaBr
c. Oxidised: NaBr
d. Reduced: Cl₂
e. Oxidation numbers before reaction: Cl= 0, Na= +1, Br= -1
f. Oxidation numbers after reaction: Cl= -1, Na= +1, Br= 0
<u>Explanation:</u>
Oxidising agents reduces themselves, oxidising other elements/compounds.
Reducing agents oxidise themselves, reducing other elements/compounds.
Oxidation is the <u>loss</u> of electrons or an <u>increase</u> in oxidation number.
Reduction is the <u>gain</u> of electrons or <u>decrease</u> in oxidation number.
Answer:
Option A.
Explanation:
Balanced equation is:
2SO₂ (g) + O₂(g) → 2SO₃(g)
First of all, we need to determine the limiting reagent. We convert mass to moles:
544.5 g . 1 mol / 64.06g = 8.5 moles of sulfur dioxide
160 g . 1mol / 32g = 5 moles of oxygen
Ratio is 1:2. 1 mol of oxygen needs 2 moles of sulfur dioxide
5 moles of oxygen may react to (5 . 2) /1 = 10 moles of SO₂
We only have 8.5 moles of SO₂ but we need 10 moles. In conclussion limiting reagent is SO₂.
Ratio is 2:2. 2 moles of SO₂ can prdouce 2 moles of SO₃
Then 8.5 moles of SO₂ must produce 3 moles of SO₃
We convert mass to moles, to determine the theoretical yield (100 % yield reaction) → 8.5 mol . 80.06 g /mol = 680.51 g
Formula for percent yield is: (Produced yield / Theoretical yield) . 100
(382 g / 680.51g) . 100 = 56.1 %