Hydrogen and carbon because they are the most common element of canyon
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Answer: Option (A) is the correct answer.
Explanation:
According to the Gibb's free energy conditions:
If
< 0, then reaction is spontaneous.
If
> 0, then reaction is non-spontaneous.
If
= 0, then reaction is equilibrium.
Since, the given reaction is
. It denotes that liquid state of fluorine is changing into gaseous state. And, the boiling point of fluorine is very low.
Therefore, at low and high temperature fluorine is a gas. Hence, the reaction is spontaneous in nature.
Thus, we can conclude that the statement at low temperature, the reaction is spontaneous and
< 0 and at high temperature, the reaction is spontaneous and
< 0, is correct.
Ksp(the solubility product constant) = [Cu⁺] [I⁻]
So, the Ksp for Cui would be:
Ksp = (2.26 × 10⁻⁶) (2.26 × 10⁻⁶) = 5.11 x 10⁻¹²
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Formula used:
K =
, where
Ksp = solubility product constant
A⁺ = cation in an aquious solution
B⁻ = anion in an aqueous solution
a, b = relative concentrations of a and b
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Definition</u></h3>
The equilibrium constant for a solid material dissolving in an aqueous solution is the SOLUBILITY PRODUCT CONSTANT, Ksp. It stands for the degree of solute dissolution in solution. A substance's Ksp value increases with how soluble it is.
Take into account the general dissolving response (in aqueous solutions) below:
aA(s)⇔cC(aq)+dD(aq)
The molarities or concentrations of the products (cC and dD) must be multiplied in order to find the Ksp. Any product that has a coefficient in front of it must be raised to the power of that coefficient (and also multiply the concentration by that coefficient).
Learn more about the concept of Ksp through the link:
brainly.com/question/1419865
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