Answer:
Al is oxidized while Ag is reduced.
Explanation:
The complete molecular equation is;
3Ag2S + 2Al --> 6Ag + Al2S3
Oxidation half equation;
2Al ------> 2Al^3+ + 6e
Reduction half equation;
6Ag^+ + 6e -------> 6Ag
Overall redox reaction equation;
2Al + 6Ag^+ ----->2Al^3+ + 6Ag
Hence; Al is oxidized while Ag is reduced.
Answer:
0.93 mol
Explanation:
Given data:
Number of moles of Na atom = ?
Number of atoms = 5.60× 10²³
Solution:
Avogadro number:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
5.60× 10²³ atoms × 1 mol / 6.022 × 10²³ atoms
0.93 mol
P = 600 mmHg
V = 2.2 L
T = 85°C
R = 0.08206 L atm / mol K
n = ?
I would start by converting the P from mmHg to atm, since our gas constant R uses atm.
600 mmHg • 1 atm / 760 mmHg = 0.789 atm = P
Then I would convert T from Celsius to Kelvin, since our gas constant R uses Kelvin.
85 + 273 = 358 K
Now you can solve PV = nRT for n, giving you:
n = PV/RT
n = (0.789 atm)(2.2 L) / (0.08206 L atm / mol K)(358 K) = 0.059 moles of gas
Answer:
22 kph
Explanation:
You simply divide the distance and the time. 66/3 = 22.
Answer:
The Bohr model and all of its successors describe the properties of atomic electrons in terms of a set of allowed (possible) values. Atoms absorb or emit radiation only when the electrons abruptly jump between allowed, or stationary, states. Direct experimental evidence for the existence of such discrete states was obtained (1914) by the German-born physicists James Franck and Gustav Hertz.
Explanation:
