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Mila [183]
3 years ago
15

What is the result of multiplying 2.5 times 10 to the power 10 by 3.5×10 to the power of -7

Chemistry
1 answer:
AURORKA [14]3 years ago
6 0

Answer:

8.75 × 10³

Explanation:

Multiply the coefficients and the exponential terms separately; then multiply them together

2.5 × 3.5 = 8.75.

When you multiply exponential terms, you add the exponents.

10¹⁰ × 10⁻⁷ = 10⁽¹⁰⁻⁷⁾ = 10³

The product is 8.75 × 10³.

A scientific calculator does the operation automatically. The buttons may have different labels on your calculator, but the key sequence is usually something like

2.5 Exp 10 × 8.5 Exp +/- 7 = 8.75×10⁻³

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It has been suggested that hydrogen gas obtained by the decomposition of water might be a substitute for natural gas (principall
Aleks [24]

Answer:

Hydrogen: -141 kJ/g

Methane: -55kJ/g

The energy released per gram of hydrogen in its combustion is higher than the energy released per gram of methane in its combustion.

Explanation:

According to the law of conservation of the energy, the sum of the heat released by the combustion and the heat absorbed by the bomb calorimeter is zero.

Qc + Qb = 0

Qc = -Qb  [1]

We can calculate the heat absorbed by the bomb calorimeter using the following expression.

Q = C . ΔT

where,

C is the heat capacity

ΔT is the change in the temperature

<h3>Hydrogen</h3>

Qc = -Qb = -C . ΔT = -(11.3 kJ/°C) . (14.3°C) = -162 kJ

The heat released per gram of hydrogen is:

\frac{-162kJ}{1.15g} =-141 kJ/g

<h3>Methane</h3>

Qc = -Qb = -C . ΔT = -(11.3 kJ/°C) . (7.3°C) = -82 kJ

The heat released per gram of methane is:

\frac{-82kJ}{1.50g} =-55kJ/g

3 0
3 years ago
What is a net ionic equation?
jolli1 [7]

Answer:

I think it will option D hope it helps

7 0
3 years ago
Q2.  0.254 g of KHP (204 g/mol) titrated against 20.0 mL of unknown NaOH (40.0 g/mol) solution to get the end point of phenolpht
Vera_Pavlovna [14]

Answer:

<u>Mass concentration (g/L) </u><u><em>= 2.49g/L.</em></u>

Explanation:

No. of moles = \frac{mass}{molar mass}

= \frac{0.254}{204} = 0.001245 moles

Concentration of KHP (C1) in litres = n/v

= \frac{0.001245}{0.02} = 0.062 mol/L

We know that:

C_{1} V_{1} = C_{2} V_{2}

where c1v1 and c2v2 are the products of concentration and volumes of KHP and NaOH respectively.

Since mole ratio is 1 : 1.

1 mole of NaOH - 40g

0.001245 mole of NaOH = 40 × 0.001245 = 0.0498g

⇒0.0498g of NaOH was used during the titration

<u><em>∴Mass concentration (g/L) = 0.0498g ÷ 0.02L</em></u>

<u><em>= 2.49g/L.</em></u>

3 0
3 years ago
What are water and carbon dioxide converted into by the end of
timama [110]

Answer:

sugar and oxygen

Explanation:

In photosynthesis, solar energy is harvested as chemical energy in a process that converts water and carbon dioxide to glucose. Oxygen is released as a byproduct.

6 0
3 years ago
Read 2 more answers
Name and describe three measures of central tendency used to summarize data.​
Yuliya22 [10]
The answer is mean,mode and median
6 0
3 years ago
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