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Vilka [71]
2 years ago
8

Students conducting a lab investigation are given two unknown tubes of colorless aqueous solutions. The students are told that o

ne tube is a salt solution and the other is a sucrose solution. How can the students determine which of the solutions contains salt?
Chemistry
1 answer:
iragen [17]2 years ago
4 0

The students can determine which of the solutions contains salt through the conductive tester.

<h3 /><h3>What is an ionic solution?</h3>

It is a solution containing ions are atoms that have gained or lost electrons to acquire a positive (lost electron) or negative (gained electron) charge.

An ionic solution would be able to conduct electricity whereas the covalent would not so if you have a conductivity tester which is available in most labs.

The students can distinguish between the 2 solutions through the conductive tester.

Learn more about the ionic solution here:

brainly.com/question/14275722

#SPJ1

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3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh
TiliK225 [7]

Answer:

n_{C_6H_{10}}=0.03molC_6H_{10}

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}

Even thought, the volume could be also computed by using its density:

V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}

Best regards.

4 0
2 years ago
Read 2 more answers
Which of the following is the best definition of a scientific theory?Help me plz
tatiyna
A scientific theory is a well tested explanation of a natural phenomenon.
7 0
3 years ago
Balance the following reaction:
NeX [460]

Answer:

3 Ca(OH)2 + 2 K3PO4 ---> Ca3(PO4)2 + 6 KOH

Explanation:

Just balance each atom on both sides.

8 0
2 years ago
Naomi has increased the pressure on a solution of liquid and gas in a closed container. What will this do to the gas in her solu
dedylja [7]

Answer:

increase the amount.

Hope this helps =)

Explanation:

5 0
3 years ago
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If 50.0 g of formic acid (hcho2, ka = 1.8 x 10^-4) and 30.0 g of sodium formate (NaCHO2) are dissolved to make 500 ml. of soluti
gizmo_the_mogwai [7]

If 50.0 g of formic acid (HCHO2, ka = 1.8 x 10^-4) and 30.0 g of sodium formate (NaCHO2) are dissolved to make 500 ml. of solution, the ph of this solution is 3.35.

Therefore, option C is the correct option.

Given,

Given mass of sodium formate = 30 g

Given mass of formic acid = 50 g

Volume of sodium formate = 500 ml

Volume of formic acid = 500ml

Molar mass of sodium formate = 68 g

Molar mass of formic acid = 46 g

<h3>To calculate concentration of sodium formate and formic acid</h3>

The ratio of number of moles and the volume of solution is Molar concentration of substance.

Concentration of sodium formate

Cb = 30/(68×500)

= 0.00088m

Concentration of formic acid

Ca = 50/(46×500)

= 0.00217m

Now,

by using Henderson hesselbalch equation,

pH = pKa + log(Cb/Ca)

pKa = -log(1.8 × 10^(-4))

= 3.75

pH = 3.75 + log(0.00088/0.00217)

pH = 3.75 - 0.392

pH = 3.35

Thus, we calculated that the value of pH of solution of formic acid and sodium formate is 3.35.

learn more about pH:

brainly.com/question/13423434

#SPJ4

3 0
2 years ago
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