What tools did you use to collect your data? 1.20 Lab: Earth's Surface Processes.

Draw a structure for a compound that meets the following description: An optically active compound, C5H10O with an IR absorption

Elenna [48]

Question: A optically active compound, C5H10O, exhibits IR absorption at 1730 cm-1.

Its carbon NMR shifts are given below. The number of hydrogen's at each carbon, determined by DEPT, is given in parentheses after the chemical shift.

13C NMR: δ 22.6 (3), 23.6 (1), 52.8 (2), 202.4 (1)

Draw the structure of this compound in the window below

Explanation:

3-methylbutanal is a butanal substituted by the methyl group at the 3rd position. It is a volatile constituent in the olive. Also, it is used as a flavoring agent and a plant metabolite, it is also a Saccharomyces cerevisiae metabolite. It is also called as the Isovaleraldehyde organic compound. The liquid is colorless at STP, and also found in very low concentrations. It is also seen to be produced commercially for different use. Mostly used compound reagent in the preparation of pharmaceuticals and pesticides.

5 0

4 years ago

A 312 g sample of a metal is heated to 277.845 °C and plunged into 200 g of water at a temperature of 11.945 °C. The final tempe

tigry1 [53]

Answer:

The specific heat capacity of the metal is 1.307 J/g °C

Explanation:

<u>Step 1:</u> Data given

mass of the metal = 312 grams

initial temperature of the metal ( before plunged in the water) = 277.845 °C

initial temperature water = 11.945 °C

Final temperature of water (and aslo the metal) = 99.062 °C

Specific heat capacity of wayer = 4.184 J/g °C

<u>Step 2:</u> Calculate the specifi heat capacity of the metal

Loss of Heat of the Metal = Gain of Heat by the Water

Qmetal = -Qwater

m(metal) * C(metal) * ΔT(metal) = - m(water) * C(water) * ΔT(water)

with mass of metal = 312 grams

with C(metal) = TO BE DETERMINED

with ΔT (metal) = 99.062 - 277.845 = -178.783 °C

with mass of water = 200 grams

with C(water) = 4.184 J/°C * g

with ΔT (water) = 99.062 - 11.945 = 87.117 °C

312 * C(metal) * -178.783 = - 200* 4.184 * 87.117

C(metal) = -72899.51 / 55780.296 = 1.307

The specific heat capacity of the metal is 1.307 J/g °C

6 0

3 years ago

The transfer of heat energy that does not require matter of any type is _____.

S_A_V [24]

This type of heat transfer is radiation since we can experience the heat from an object without being in contact with it. Energy is being emitted by electromagnetic waves or in moving subatomic particles. Radiation is a consequence of thermal agitation of the molecules.

6 0

3 years ago

Read 2 more answers

What is the molality of a solution of water and kcl if the freezing point of the solution is –3mc030-1.jpgc?

Natasha_Volkova [10]

We will use the expression for freezing point depression ∆Tf
∆Tf = i Kf m
Since we know that the freezing point of water is 0 degree Celsius, temperature change ∆Tf is
∆Tf = 0C - (-3°C) = 3°C
and the van't Hoff Factor i is approximately equal to 2 since one molecule of KCl in aqueous solution will produce one K+ ion and one Cl- ion:
KCl → K+ + Cl-
Therefore, the molality m of the solution can be calculated as
3 = 2 * 1.86 * m
m = 3 / (2 * 1.86)
m = 0.80 molal

4 0

3 years ago

How are liquids and solids similar? Check all that apply.

Ulleksa [173]

Answer:

d

Explanation:

7 0

3 years ago