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3 years ago

Please help!! thanks you whoever can answer this for me <3

Mathematics

2 answers:

SVETLANKA909090 [29]3 years ago

8 0

Alternate means opposite in a way, and the only answer that gives us "opposite angles" is D. angle 4 and angle 6.

Korvikt [17]3 years ago

4 0

Its A because none of the other answers have 12 in them and it crosses 12

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Solve the right triangle

defon

I recommend learning the mnemonic SOHCAHTOA (it's very fun to say!)
Here is what SOHCAHTOA represents.

Sin - Opposite / Hypotenuse (SOH)
Cos - Adjacent / Hypotenuse (CAH)
Tan - Opposite / Adjacent (TOA)

The sine of an angle is the length of the side opposite of the angle divided by the length of the hypotenuse.

Thus, the length of the side opposite of the angle divided by the sine will give us the length of the hypotenuse.

The angle is 46 degrees. The length of the side opposite of the angle is 14. The hypotenuse is c.

$c= \dfrac{14}{\sin{46^o}}$

$\approx 19.46$

The tangent of an angle is the length of the side opposite of the angle divided by the length of the side adjacent to the angle.

Thus, the length of the side opposite to the angle divided by the tangent of the angle will give us the length of the other leg.

The length of the side opposite to the angle is 14. The angle is 46. The unknown length of the side adjacent to the angle is b.

$b=\dfrac{14}{\tan{46^o}}$

$\approx 13.52$

This should be what you are looking for. Enjoy!

6 0

3 years ago

I will mark brainiest is my answer is correct?

Alex Ar [27]

Your answer is correct

5 0

3 years ago

Which statement describes a force between charged particles

nekit [7.7K]

A. Like charges repel each other. Just think opposites attract for charged particles.

6 0

3 years ago

Read 2 more answers

Someone please help me!!!!

BARSIC [14]

Answer: see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity: cos 2A = 2cos²A - 1

Use the Difference Identity: cos (A - B) = cosA · cosB + sinA · sinB

Use the Unit Circle to evaluate: cos (π/2) = 0 & sin (π/2) = 1

<u>Proof LHS → RHS</u>

$\text{Given:}\qquad \qquad \qquad \qquad 2\cos^2\bigg(\dfrac{\pi}{4}-\dfrac{A}{2}\bigg)-1\\\\\\\text{Double Angle Identity:}\quad \cos2\bigg(\dfrac{\pi}{4}-\dfrac{A}{2}\bigg)\\\\\\\text{Simplify:}\qquad \qquad \qquad \quad \cos\bigg(\dfrac{\pi}{2}-A\bigg)\\\\\\\text{Difference Identity:}\qquad \cos\dfrac{\pi}{2}\cdot \cos A+\sin \dfrac{\pi}{2}\cdot \sin A\\\\\\\text{Unit Circle:}\qquad \qquad \qquad 0\cdot \cos A+1\cdot \sin A\\\\\\\text{Simplify:}\qquad \qquad \qquad \qquad \sin A$

LHS = RHS: sin A = sin A $\checkmark$

4 0

4 years ago

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Plz help due tomorrow

vodomira [7]

Answer:

Step-by-step explanation:

4h/5

6 0

3 years ago

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