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cricket20 [7]
3 years ago
12

# 1) 22 students are __% of 55 * Show Work *

Mathematics
2 answers:
tamaranim1 [39]3 years ago
7 0

40% for number 1 So all you have to do is identify the parts of the equation. We don't know the percent, but we know everything else, so we can plug what we know into the equation

P

×

55

=

22

55

22

=

P

P

=

0.4

=

40

%

Related questions

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75

%

on a test worth  

46

points. How many points did he get correct?

How do you use proportions to solve percent equations?

How do you translate percent problems into an equation?

What number is 32% of 600?


LenaWriter [7]3 years ago
5 0

22 = p* 55

divide by 55

22/55 = p

.4 = p

40 percent


24 = .40 * m

divide by .40

24/.4 = m

60 = m

60 marbles


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A store has a sale with 10% off every item. When you enter the store, you receive a coupon that states that you receive an addit
sweet [91]

Step-by-step explanation:

Step one:

We are told that the store offers off 10% of sales, this means that the store is offsetting the price down by 10% hence a price reduction.

Moreso, <em>a coupon is a voucher entitling the holder to a discount off a particular product</em>. the coupon is 40%, hence this is equal to a discount, that is price reduction by 40%.

Step two:

<em>Say the price of an item is $100, a coupon if 40% will entitle the holder to only pay $60, that is</em>

=40/100*100

=0.4*100

=$40 off

= 100-40

=$60

<u>The total percent of reduction 10+40= 50%</u>

<u>This is equal to a discount on the sales price</u>

7 0
3 years ago
Which measures are $1 greater for Group B than for Group A?
Marrrta [24]

Answer: C

the mean and the median

Step-by-step explanation:

From the attached table,

The range of group A = 5 - 0 = 5

The range of group B = 4 - 1 = 3

Difference in range is not equal to $1

The mode of A = 1

The mode of B = 3

Difference in mode is not equal to $1

The median of A = (1 + 2)/2 = 1.5

The median of B = 3

Difference = 3 - 1.5 = $1.5

The mean of A = 16/15 = 1.07

The mean of B = 40/15 = 2.67

The difference = $1.6

From the above analysis, we can therefore conclude that non of the measures are $1 greater for Group B than for Group A

The best option among the options is

the mean and the median

8 0
4 years ago
Read 2 more answers
The hypotenuse AB of a right triangle ABC is 5 ft, and one leg, AC, is decreasing at the rate of 2 ft/sec. The rate, in square f
mojhsa [17]
Okay 
we have the rate of change of AC = d(AC)/dt = -2 
the rate of change od BC = d(BC)/dt 
area = (1/2) *AC) (BC) 
taking differential on both sides we ge 
d(A)/dt = 1/2){ (BC) d(AC)/dt + (AC) d(BC)/dt)}....(1) 
again 
when AC= 3 
applying pythagorous thm 
we get 
(5)^2 =(3)^2 +(BC)^2 
hence we get BC = 4 
now we need to find d(BC)/dt 
we have 
(5)^2 = (AC)^2 +(BC)^2 
taking differenial 
0=2(AC) d(AC/dt) +2BC d(BC)/dt 
that is 
d(BC)/dt = -(3) *(-2)/4 ..(at AC =3) 
hence 
d(BC)/dt = 3/2 
substituting these values in equation (1) 
d(A)/dt = (1/2) {4 * -2 + 3 *3/2} 

which gives 
<span>d(A)/dt = -7/4 

</span>The rate, in square feet per second, at which <span>the area is changing when AC = 3 is -7/4 ft/sec.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

</span>
4 0
3 years ago
Read 2 more answers
Write the equation of the line that passes through (-1,4) and parallel to -x + 2y = 6.
NARA [144]

Answer:

make y the subject first

Step-by-step explanation:

y=x/2 +3

parallel lines have equal gradient m1=m2

y-y1=m(x-x1)

y-4=1/2(x-(-1))

y=1/2(x) +1/2+4

final answer

y=1/2(x) +9/2

3 0
3 years ago
Help plz I need help ASAP!!!!!!!!!!!!!!!!!!!
astraxan [27]

So, each square on the grid is 10 inches in length and width

To find the dimension of the diagonal lengths, treat them like a hypotenuse so we can use the Pythagorean theorem.

a^2 + b^2 = c ^2

a and b are our length and width and c is the hypotenuse.

Make each diagonal length part of a triangle. There will then be 4 triangles to work with.

Triangle 1 (Top left)

Triangle 2 (Bottom left)

Triangle 3 (Top Right)

Triangle 4 (Bottom Right)

A right triangle made with the top left diagonal dimension will have a vertical dimension of 30 (10+10+10) and a horizontal dimension of 40 (10+10+10+10)

To find c or the hypotenuse, plug these into the Pythagorean theorem.

30^2 + 40^2 = c ^2

c^2 = 900 + 1600 = 2500

c = sqrt(2500) = 50

You will see that triangles 2, 3, and 4 have the same vertical and horizontal dimensions giving them the same value.

Now combine the dimensions

diagonal = 50+50+50+50 = 200

horizontal = 90+90 = 180

diagonal + horizontal = 380

4 0
4 years ago
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