Step-by-step explanation:
Step one:
We are told that the store offers off 10% of sales, this means that the store is offsetting the price down by 10% hence a price reduction.
Moreso, <em>a coupon is a voucher entitling the holder to a discount off a particular product</em>. the coupon is 40%, hence this is equal to a discount, that is price reduction by 40%.
Step two:
<em>Say the price of an item is $100, a coupon if 40% will entitle the holder to only pay $60, that is</em>
=40/100*100
=0.4*100
=$40 off
= 100-40
=$60
<u>The total percent of reduction 10+40= 50%</u>
<u>This is equal to a discount on the sales price</u>
Answer: C
the mean and the median
Step-by-step explanation:
From the attached table,
The range of group A = 5 - 0 = 5
The range of group B = 4 - 1 = 3
Difference in range is not equal to $1
The mode of A = 1
The mode of B = 3
Difference in mode is not equal to $1
The median of A = (1 + 2)/2 = 1.5
The median of B = 3
Difference = 3 - 1.5 = $1.5
The mean of A = 16/15 = 1.07
The mean of B = 40/15 = 2.67
The difference = $1.6
From the above analysis, we can therefore conclude that non of the measures are $1 greater for Group B than for Group A
The best option among the options is
the mean and the median
Okay
we have the rate of change of AC = d(AC)/dt = -2
the rate of change od BC = d(BC)/dt
area = (1/2) *AC) (BC)
taking differential on both sides we ge
d(A)/dt = 1/2){ (BC) d(AC)/dt + (AC) d(BC)/dt)}....(1)
again
when AC= 3
applying pythagorous thm
we get
(5)^2 =(3)^2 +(BC)^2
hence we get BC = 4
now we need to find d(BC)/dt
we have
(5)^2 = (AC)^2 +(BC)^2
taking differenial
0=2(AC) d(AC/dt) +2BC d(BC)/dt
that is
d(BC)/dt = -(3) *(-2)/4 ..(at AC =3)
hence
d(BC)/dt = 3/2
substituting these values in equation (1)
d(A)/dt = (1/2) {4 * -2 + 3 *3/2}
which gives
<span>d(A)/dt = -7/4
</span>The rate, in square feet per second, at which <span>the area is changing when AC = 3 is -7/4 ft/sec.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
Answer:
make y the subject first
Step-by-step explanation:
y=x/2 +3
parallel lines have equal gradient m1=m2
y-y1=m(x-x1)
y-4=1/2(x-(-1))
y=1/2(x) +1/2+4
final answer
y=1/2(x) +9/2
So, each square on the grid is 10 inches in length and width
To find the dimension of the diagonal lengths, treat them like a hypotenuse so we can use the Pythagorean theorem.
a^2 + b^2 = c ^2
a and b are our length and width and c is the hypotenuse.
Make each diagonal length part of a triangle. There will then be 4 triangles to work with.
Triangle 1 (Top left)
Triangle 2 (Bottom left)
Triangle 3 (Top Right)
Triangle 4 (Bottom Right)
A right triangle made with the top left diagonal dimension will have a vertical dimension of 30 (10+10+10) and a horizontal dimension of 40 (10+10+10+10)
To find c or the hypotenuse, plug these into the Pythagorean theorem.
30^2 + 40^2 = c ^2
c^2 = 900 + 1600 = 2500
c = sqrt(2500) = 50
You will see that triangles 2, 3, and 4 have the same vertical and horizontal dimensions giving them the same value.
Now combine the dimensions
diagonal = 50+50+50+50 = 200
horizontal = 90+90 = 180
diagonal + horizontal = 380
