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xxMikexx [17]
3 years ago
6

What is the smallest power of 10 that would exceed 987,645,321,098,755,432

Mathematics
1 answer:
madam [21]3 years ago
8 0

Answer:

Step-by-step explanation:

1000000000000000

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Using the digits 1 to 9 at most one time each, fill in the boxes to make the equality true:
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(4+5-2+1)- (7+3-8+6) = 0

Step-by-step explanation:

you look for what numbers when subtracted equal zero (in this case each of the parentheses is 8) in each of the parentheses and combine them at the end to form the final equation.  

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In a parallelogram consecutive angles are
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Which table of ordered pairs represents a proportional relationship?<br> plss help!
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The second graph because 2x5=10, 4x5=20, 6x5=30!
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2
Aleksandr [31]

Answer: lower bound = 9550

<u>Step-by-step explanation:</u>

Since the number is rounded to the nearest hundred, the actual value is somewhere between 9550 (which rounds up to 9600) and 9649 (which rounds down to 9600).

The lower bound is: 9550

The upper bound is: 9649

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3 years ago
PLZ HELP ASAP!!!!! <img src="https://tex.z-dn.net/?f=" id="TexFormula1" title="" alt="" align="absmiddle" class="latex-formula">
AveGali [126]

The simplified expression of  $4 x \cdot \frac{1}{x^{-5}} \cdot x^{-3} is 4x^3.

Solution:

Given expression is 4 x \cdot \frac{1}{x^{-5}} \cdot x^{-3}.

To simplify the given expression.

$\Rightarrow4 x \cdot \frac{1}{x^{-5}} \cdot x^{-3}

Using exponent rule: \frac{1}{a^{-m}}=a^m

$\Rightarrow4x \cdot x^{5}.x^{-3}

Using another exponent rule: a^m \cdot a^n=a^{m+n}

$\Rightarrow4x \cdot x^{5-3}

$\Rightarrow4x \cdot x^{2}

Using exponent rule: a^m \cdot a^n=a^{m+n}

$\Rightarrow4x^{1+2}

$\Rightarrow4x^3

Hence the simplified expression of  $4 x \cdot \frac{1}{x^{-5}} \cdot x^{-3} is 4x^3.

8 0
3 years ago
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