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sineoko [7]
3 years ago
11

Find an equation of the line containing the point (3,3) and parallel to y = 2 x − 1 y=2x-1.

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0
Y=mx+b
y=2x+b
then substitute x and y
3=2(3) + b
3= 6 + b
b=-3
y=2x-3
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Answer:

2 should be distributed as 2y + 8; y = 4

Step-by-step explanation:

2(y + 4) = 4y

Distribute

2y + 8 = 4y

Step 2 is incorrect because the added instead of multiplied

Continuing on to correct the problem

Subtract 2y from each side

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-16t^2+729 < 104

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Multiplying the inequality by -1:

(-1)(-16t^2 < -625)

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Replacing t^2 by [ Absolute value (t) ]^2:

[ Absolute value (t) ]^2 > 39.0625

Square root both sides of the inequality:

sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)

Absolute value (t) > 6.25

t < -6.25 or t > 6.25, but t can not be negative, then the solution is:

t > 6.25



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