Answer:
5 significant figures
Step-by-step explanation:
Any first number than starts with > 0, it is counted as significant figures and with 0 in the middle of number, also will be counted. But if the first number is 0, you have to skip to the next number.
e.g
0.0567 = 3s.f
1.542 = 4s.f
0.0000012 = 2s.f
1200586 = 7s.f
87000000002 = 11s.f
Answer:
0.666666667
Step-by-step explanation:
Answer:
B. -3
Step-by-step explanation:
Starting from the y-intercept of [0, -2], you do <em>rise\</em><em>run</em><em> </em>by either moving three blocks <em>north</em><em> </em>over<em> </em>one block <em>west</em><em>,</em><em> </em>or three blocks <em>south</em><em> </em>over one block <em>east</em><em> </em>[<em>west</em> and <em>south</em> are negatives].
I am joyous to assist you anytime.
the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
