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lawyer [7]
3 years ago
12

-6x - 12 < 36 please help me​

Mathematics
2 answers:
KiRa [710]3 years ago
8 0

Answer:

x > -8

Step-by-step explanation:

i hope this helps :)

Drupady [299]3 years ago
7 0
X>-8 this is easy well at least for me
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Directions: Type the correct answer in each box. Write the coordinates in the form (x, y). If necessary, use / for the fraction
Zanzabum

Answer:

-10.25,-3.75 then the next one is -5.75,-10.75

Step-by-step explanation:

8 0
3 years ago
How would I do this?
Lelu [443]
I'm not sure about part B, but part A will have the answer "if Ron eats lunch today, then he will drink a glass of milk" (without quotes of course)

The idea is that we have these arguments in symbolic form
P = Ron eats lunch today
Q = Ron eats a sandwich
R = Ron will drink a glass of milk

The format is 
"If P then Q" ----> "if Q then R"  so therefore "If P then R"

We see that P leads to Q, then Q leads to R. So overall P leads to R. We connect them as a chain of sorts. We can skip over Q since we know the first point will lead to the last. Think of it as a shortcut of sorts.
8 0
3 years ago
Which statement BEST explains the relationship between lines GF &amp; HJ?
Pavel [41]

Answer:

Option (4)

Step-by-step explanation:

Slope a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

m = \frac{y_2-y_1}{x_2-x_1}

Since, blue line is passing through two points (-4, -2) and (0, 4),

Slope of the blue line = \frac{4+2}{0+4}

                                    = \frac{3}{2}

Similarly, green line is passing through two points (-4, 1) and (0, -2),

Slope of the green line = \frac{1+2}{-4-0}

                                       = -\frac{3}{4}

Since, \frac{3}{2}\neq -\frac{3}{4}

Neither these slopes are opposite reciprocals.

Therefore, both the lines are neither parallel nor perpendicular.

Option (4) will be the correct option.

6 0
2 years ago
- Which of the following is the correct distance between the points (-5, 3) and (7,8)?
JulsSmile [24]

Answer:

13 units

Step-by-step explanation:

(x₁,y₁) = (-5 , 3)   & (x₂ , y₂) = (7 ,8)

Distance = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}} \\

              = \sqrt{(7-[-5])^{2}+(8-3)^{2}} \\\\= \sqrt{(7+5)^{2}+(8-3)^{2}} \\\\=  \sqrt{(12)^{2}+(5)^{2}}\\\\=\sqrt{144+25}\\\\=\sqrt{169}\\\\= 13

7 0
2 years ago
Solve the following equation <br>2x to the power 2 - 3x - 2 = 0
vitfil [10]

Eliminate the opponent number

- 3x = 0

Change the sign of both sides of the equation

3x = 0

Divide both sides by the same number

x = 0

<h2>#HopeItHelps</h2>

<h3>#MarkAsBrainlist </h3>

#KeepStudying

3 0
2 years ago
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