So you need to divide 1000 by 125 which is 8. Which then you times by two to equal the two kilograms. So he needs to fill the cup up 16 times.
Median and IQR are the most appropriate measures of center and spread for this data set.
<h3>Why are
Median and IQR the most appropriate?</h3>
Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:
- Mean is affected by extreme values
- Mean is not correct if more outliers are present
- Mean may not represent the nature of the data whether skewed right or left.
Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,
Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.
Therefore, Option B is correct.
Read more about measures of center
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Question:
A sample of cans of peaches was taken from a warehouse, and the content of each can mearsed for weight. the sample means was 486g with stand deviation 6g. state the weight percentage of cans with weight:
Draw normal curve to help - split into 8 section ( i can't draw it here)
a) 34.13% of cans will be between 480g and 486g.
b) 13.59 + 2.15 + 0.13= 15.87% of cans greater than 492g.
Look at the Stand Dev Graph where the give you the number
Step-by-step explanation:
Let me give you a different question and i will answer it, which you help you answer your question.
5/2 * 6 = 15
h/6 * 6 = h
so
h = 15
The school is 15ft tall
