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disa [49]
3 years ago
5

NEED HELP

Chemistry
1 answer:
Leona [35]3 years ago
5 0
<h3>Zinc +oxygen - zinc oxide</h3>

<h3><em>chlorine</em><em>+</em><em> </em><em>magnesium</em><em> </em><em>-</em><em> </em><em>magnesium</em><em> </em><em>dichloride</em></h3><h3><em>iron</em><em> </em><em>+</em><em> </em><em>arsenic</em><em> </em><em>-</em><em> </em><em>ferric</em><em> </em><em>arsenate</em></h3>

<h2><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Hope</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>helpful</em><em> </em><em>for</em><em> </em><em>you</em></h2>

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Answer:

Weight is the measure of the force of gravity on an object. The mass of an object will never change, but the weight of an item can change based on its location. For example, you may weigh 100 pounds on Earth, but in outer space you would be weightless.

Explanation:

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8 0
2 years ago
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water’s molar mass is 18.01 g/mol. The molar mass of glycerol is 92.09 g/mol. At 25 celsius, glycerol is more viscous than water
Gemiola [76]

Answer is: glycerol because it is more viscous and has a larger molar mass.

Viscosity depends on intermolecular interactions.

The predominant intermolecular force in water and glycerol is hydrogen bonding.

Hydrogen bond is an electrostatic attraction between two polar groups in which one group has hydrogen atom (H) and another group has highly electronegative atom such as nitrogen (like in this molecule), oxygen (O) or fluorine (F).

4 0
3 years ago
You pour 25.0 mL of 6.70 M NaOH stock solution into your beaker. How much water will you have if it is diluted to 3.40 M
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If we place the like poles of two magnets facing each other what will happen?
Leviafan [203]
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8 0
3 years ago
At a particular temperature a 2.00-L flask at equilibrium contains 2.80 ✕ 10-4 mol N2, 2.50 ✕ 10-5 mol O2, and 2.00 ✕ 10-2 mol N
zhenek [66]

Answer : The value of equilibrium constant (K) is, 5.71\times 10^4

Explanation :

First we have to calculate the concentration of N_2,O_2\text{ and }N_2O

\text{Concentration of }N_2=\frac{\text{Moles of }N_2}{\text{Volume of solution}}=\frac{2.80\times 10^{-4}mol}{2.00L}=1.4\times 10^{-4}M

and,

\text{Concentration of }O_2=\frac{\text{Moles of }O_2}{\text{Volume of solution}}=\frac{2.50\times 10^{-5}mol}{2.00L}=1.25\times 10^{-5}M

and,

\text{Concentration of }N_2O=\frac{\text{Moles of }N_2O}{\text{Volume of solution}}=\frac{2.00\times 10^{-2}mol}{2.00L}=1.00\times 10^{-2}M

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

N_2(g)+O_2(g)\rightarrow 2N_2O(g)

The expression for equilibrium constant is:

K=\frac{[N_2O]^2}{[N_2][O_2]}

Now put all the given values in this expression, we get:

K=\frac{(1.00\times 10^{-2})^2}{(1.4\times 10^{-4})\times (1.25\times 10^{-5})}

K=5.71\times 10^4

Thus, the value of equilibrium constant (K) is, 5.71\times 10^4

7 0
3 years ago
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