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Slav-nsk [51]
3 years ago
11

Determine the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sampl

e of the sulfuric acid solution?
Chemistry
1 answer:
77julia77 [94]3 years ago
7 0

Answer:

<u></u>

  • <u>0.37M</u>

Explanation:

Since sulfuric acid, H₂SO₄, is a diprotic acid and potassum hydroxide, KOH, contains one OH⁻ in the formula, the number of moles of potassium hydroxide must be twice the number of moles of sulfuric acid.

<u>1. Determine the number of moles of KOH in 47mL of 0.39M potassium hydroxide solution</u>

  • number of moles = molarity × volume in liters
  • number of moles = 0.39M × 47mL × 1liter/1,000 mL = 0.1833mol

<u>2. Determine the number of moles of sulfuric acid needed</u>

  • number of moles of H₂SO₄ = number of moles of KOH/2 = 0.1833/2 = 0.009165mol

<u>3. Determine the concentration that contains 0.009165 mol in 25mL of the acid.</u>

  • Molarity = number of moles / volume in liters
  • M = 0.009165mol/(25mL) × (1,000mL/liter) = 0.3666M

Round to two significant figures: 0.37M

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