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lapo4ka [179]
3 years ago
5

Wadadaaaaddddddddddddddddddddddddddd

Chemistry
1 answer:
timama [110]3 years ago
5 0

Answer:

Huhuuhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Explanation:

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The thin outer layer of Earth, called the crust, contains only 0.50 percent of Earth's total mass and yet is the source of almos
Rzqust [24]

Answer:

The mass of silicon in kilograms in Earth's crust is7.2729\times 10^{21} kg.

Explanation:

Mass of Earth =5.9\times 10^{21} tons

(1 ton= 2000 lb)

(1 lb =453.6 g)

1 ton = 2000 × 453.6 g =907,200 g

Mass of Earth =5.9\times 10^{21}\times 907,200 g=5.3524\times 10^{27} g

Percentage of earth crust = 0.50%

Mass of earth crust = M

0.50\%=\frac{M}{5.3524\times 10^{27}}\times 100

M=2.6762\times 10^{25} g

Percentage of the silicon in Earth's crust = 27.2 %

Mass of silicon in in Earth's crust = m

Si\%=\frac{m}{M}\times 100

27.2\%=\frac{m}{2.6762\times 10^{25} g}\times 100

m = 7.2792\times 10^{24} g=7.2729\times 10^{21} kg

1000 g = 1 kg

The mass of silicon in kilograms in Earth's crust is7.2729\times 10^{21} kg.

7 0
3 years ago
Which element is found in all the acids described in this section?
mixer [17]
Acids contain hydrogen!
8 0
3 years ago
Give the orbital notation for a neutral atom of titanium
dedylja [7]

Answer:

Explanation:

A neutral titanium atom will have 22 electrons. Therefore, its electron configuration will be 1s2 2s2 2p6 3s2 3p6 4s2 3d2.

5 0
3 years ago
If you set up an experiment with two different independent variables, then the results would be_____.
MariettaO [177]

Answer: A) Inconclusive; you would not know which of the two variables caused the change.

Explanation:

When you set up an experiment, you must make sure that you control the variables such that only one independent variable changes at a time, while all the remainder conditions (the other independent variables) are controlled (fixed).

By observing (measuring) the dependent variable, while only one independent variable changes you can understandhow such independent variable explains (determines) the dependent variable, leading to a conclusion.

Conversely, if two or more independent variables change at a time, then there is no way that you can tell how the output (dependent variable) is related with one or other of the changes of the indipendent variables. You wolud not be able to discriminate (distinguish) the effect of one or other variable, making the experiment inconclusive

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4 0
3 years ago
Low concentrations of EDTA near the detection limit gave the following dimensionless instrument readings: 175, 104, 164, 193, 13
Mila [183]

Answer:

Following are the solution to these question:

Explanation:

Calculating the mean:

\bar{x}=\frac{175+104+164+193+131+189+155+133+151+176}{10}\\\\

  =\frac{1571}{10}\\\\=157.1

Calculating the standardn:

\sigma=\sqrt{\frac{\Sigma(x_i-\bar{x})^2}{n-1}}\\\\

Please find the correct equation in the attached file.

=28.195

For point a:

=3s+yblank \\\\=3 \times 28.195+50\\\\=84.585+50\\\\=134.585\\

For point b:

=3 \ \frac{s}{m}\\\\ = \frac{(3 \times 28.195)}{1.75 \times 10^9 \ M^{-1}}\\\\= 4.833 \times 10^{-8} \ M

For point c:

= 10 \frac{s}{m} \\\\= \frac{(10 \times 28.195)}{1.75 x 10^9 \ M^{-1}}\\\\ = 1.611 \times 10^{-7}\  M

It is calculated by using the slope value that is 1.75 \times 10^9 M^{-1}. The slope value 1.75 \times 10^9 M^{-1}is ambiguous.

7 0
3 years ago
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