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lapo4ka [179]
3 years ago
5

Wadadaaaaddddddddddddddddddddddddddd

Chemistry
1 answer:
timama [110]3 years ago
5 0

Answer:

Huhuuhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Explanation:

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vesna_86 [32]
That an ip leak don’t trust it ^^^^^^^^^^
5 0
2 years ago
the average kinetic energy of the particles in a gas increases as the temperature of the gas increases. explain​
sveticcg [70]

Answer:

Explanation: Volume versus Temperature: Raising the temperature of a gas increases the average kinetic energy and therefore the rms speed (and the average speed) of the gas molecules. Hence as the temperature increases, the molecules collide with the walls of their containers more frequently and with greater force.

7 0
3 years ago
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Atomic mass of nitrogen
erma4kov [3.2K]

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8 0
3 years ago
2.247 liter to milliliter
gladu [14]

Answer:

2247 mililiters

Explanation:

6 0
3 years ago
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Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

brainly.com/question/20305871

#SPJ1

5 0
1 year ago
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