A single water molecule can form 4 Hydrogen Bonds.
A hydrogen atom that is linked to a highly electronegative atom and another highly electronegative atom that is close by interact with one another to form hydrogen bonds, which are an unique kind of attractive intermolecular interactions. This process is known as hydrogen bonding. Hydrogen, for instance, is covalently linked to the more electronegative oxygen atom in water molecules (H2O). Therefore, the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another H2O molecule are what cause hydrogen bonding to form in water molecules.
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Answer:
- Density Liquid = 0.841 g/mL
- Density Metal = 2.711 g/cm³
Explanation:
- The density of the liquid is:
Mass Liquid / Volume Liquid
From the problem we know that Volume Liquid = 25.0 mL, <u>the mass of the liquid can be calculated by substracting masses</u>:
- Mass Liquid + Mass Slug + Mass Empty Cylinder = 125.934 g
- Mass Liquid + 15.454 g + 89.450 g = 125.934 g
- Mass Liquid = 125.934 g - 15.454 g - 89.450 g
Thus the density of the liquid is:
Density Liquid = 21.030 g / 25.0 mL = 0.841 g/mL
2. The density of the metal slug is:
Mass Metal / Volume Metal
We already know that the mass of the slug is 15.454 g. Its volume can be calculated using <em>Archimede's principle</em>, which states that the volume of an object is equal to the volume of liquid it displaces, in other words:
Volume Metal = 30.7 mL - 25.0 mL = 5.7 mL
Thus the density of the metal slug is
Density Metal = 15.454 g / 5.7 mL = 2.711 g/mL = 2.711 g/cm³
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Answer:</h2>
Average atomic mass of an element is the sum of the masses of its isotopes each multiplied by its natural abundance
The water is formed from oxygen gas and...hydrogen gas, I'm assuming? It would have been nice for the question to have been a bit more explicit (not blaming you, of course).
Assuming that's the case, our chemical reaction would be:
2H₂(g) + O₂(g) → 2H₂O(l).
We are told that 1 mol of a gas has a volume of 24.0 dm³ at RTP. We can use this relation to determine the number of moles of O₂ gas that reacts given its initial volume, 33.5 dm³.
33.5 dm³ O₂(g)/24.0 dm³/mol = 1.396 mol O₂(g).
Since we are not given any information about H₂(g), or any other reactant for that matter, I am assuming that the O₂(g) is the limiting reactant. According to the equation, the stoichiometric ratio between O₂ and H₂O is 1:2. That is, for every one mole of O₂ that is consumed, two moles of H₂O are formed (i.e., the number of moles of H₂O formed is double the number moles of O₂).
Since 1.396 moles of O₂ reacts, 2(1.396) = 2.792 moles of H₂O are produced. To convert moles of water to grams, we multiply the number of moles of H₂O by the molar mass of H₂O:
(2.792 moles H₂O)(18.015 g/mol) = 50.3 g H₂O.
So, approximately 50.3 grams of water are formed from 33.5 dm³ of oxygen gas at RTP.