The <em>correct answers</em> are:
C) No: we would need to know if the vertex is a minimum or a maximum; and
C)( 0.25, 5.875).
Explanation:
The domain of any quadratic function is all real numbers.
The range, however, would depend on whether the quadratic was open upward or downward. If the vertex is a maximum, then the quadratic opens down and the range is all values of y less than or equal to the y-coordinate of the vertex.
If the vertex is a minimum, then the quadratic opens up and the range is all values of y greater than or equal to the y-coordinate of the vertex.
There is no way to identify from the coordinates of the vertex whether it is a maximum or a minimum, so we cannot tell what the range is.
The graph of the quadratic function is shown in the attachment. Tracing it, the vertex is at approximately (0.25, 0.5875).
Answer:
n = 16
Step-by-step explanation:
The slope from the origin to each point must be equal
(0,0) and (n, 8)
m = 8/n
(0, 0) and (32, n)
m = n/32
Set the slopes equal
8/n = n/32
cross multiply
256 = n²
Take the square root of both sides
n = 16
The ratio is 8:20
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The value of x is 15° and the type of quadrilateral is a rhombus.
<h3>
Quadrilateral</h3>
- A quadrilateral is a polygon that has four sides.
- The sum of all angles of a quadrilateral is 360°.
Here, we are given,
m∠A = (7x)◦, m∠B = (4x + 5)◦, m∠C =(6x + 15)◦, m∠D = (6x −5)◦
So, we will have
7x+4x+5+6x+15+6x-5=360°
23x+15°=360°
23x=345°
x=345°/23°
x=15°
Hence, the angles of the quadrilateral are:
m∠A = (7x)◦=105°,
m∠B = (4x + 5)◦ =65°
m∠C =105°
m∠D = (6x −5)◦ =85°
Since the diagonal bisects ∠B and ∠D, we get that the quadrilateral is a rhombus.
To learn more about rhombus refer to:
brainly.com/question/27870968
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−1 1/5+(−3/5)
Convert -1 1/5 into improper fraction
-6/5+(-3/5)
Add -3/5 to -6/5. This would be the same as subtracting 3/5 from -6/5
<span>Final Answer: -9/5 or -1 4/5</span>
