Question

Use the conversion factor 1amu=6.66054 x 10^-24 to answer the following questions.. . a) 1.674 x 10^-24 g of neutrons is how many amu?. . b)what is the mass in grams of one lithium atom(lithium has an atomic weight of 6.94 amu). . c)6.492 x 10^-23 g of potassium is how many amu?

Answer 1

A.) The conversion factor is 1 amu = $1.66054 ^{-24}g$

To know how many amu in $1.674x10^{-24}g$ grams of neutrons:
$1.674x10^{-24}g ( \frac{x (amu) }{ 1.66054x10^{-24} g)}$

=1.00811 amu

b.) The mass in grams of one lithium ion which has an atomic weight of 6.94 amu.

$6.94 amu (\frac{6.66054 ^{-24} g}{1 amu})$ = $4.62241x10 ^{23} g$

c.) How many amu in 6.492x10^-23g potassium?

$6.492x10^{-23}g ( \frac{x (amu) }{ 1.66054x10^{-24}g })$ = 39.0957 amu

Answer 2

Answer :

(a) The number of amu is 1.008 amu.

(b) The mass of one lithium atom is $11.5\times 10^{-24}g$

(c) The number of amu is 39.09 amu.

Explanation :

As we are given that conversion factor:

$1amu=1.66054\times 10^{-24}g$

(a) To calculate the number of amu.

As, $1.66054\times 10^{-24}g$ of neutrons = 1 amu

So, $1.674\times 10^{-24}g$ of neutrons = $\frac{1.674\times 10^{-24}g}{1.66054\times 10^{-24}g}\times 1amu=1.008amu$

Thus, the number of amu is 1.008 amu.

(b) To calculate the mass of one lithium atom.

As, 1 amu of lithium atom = $1.66054\times 10^{-24}g$

So, 6.94 amu of lithium atom = $6.94\times 1.66054\times 10^{-24}g=11.5\times 10^{-24}g$

Thus, the mass of one lithium atom is $11.5\times 10^{-24}g$

(c) To calculate the number of amu.

As, $1.66054\times 10^{-24}g$ of neutrons = 1 amu

So, $6.492\times 10^{-23}g$ of neutrons = $\frac{6.492\times 10^{-23}g}{1.66054\times 10^{-24}g}\times 1amu=39.09amu$

Thus, the number of amu is 39.09 amu.