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Andreas93 [3]
3 years ago
8

Sn + 2HCI --> SnCl2 + Hz

Chemistry
1 answer:
GaryK [48]3 years ago
5 0

Answer:

Option B. Single replacement reaction

Explanation:

To know which option is correct, it is important that we know the definition of each option. The definition of each option is given below:

1. Synthesis reaction is a reaction in which two different elements or compound combine together to produce a new compound different from the two starting elements or compound. An example is illustrated below:

C + D —> E

2. Single replacement reaction is a reaction in which an element replaces or displaces another element in a compound. An example is illustrated below:

D + BC —> B + CD

3. Combustion reaction is a reaction in a substance react with oxygen to generate carbon dioxide (CO₂) and water (H₂O). An example can be seen when organic compound react with oxygen to produce carbon dioxide (CO₂) and water (H₂O). This is illustrated below:

CₓHᵧ + (x + y/4) O₂ —> xCO₂ + (y/2) H₂O

4. Double replacement reaction is a reaction in which the ions of the two reacting compound replaces one another to form new products. This is illustrated below:

X⁺Y¯ + U⁺V¯ —> X⁺V¯ + U⁺Y¯

5. Decomposition reaction is a reaction in which a large compound breaks down into two or more elements or compound. An example is illustrated below:

GH —> G + H

Now, observing the equation given in the question above:

Sn + 2HCl —> SnCl₂ + H₂

We can see that Sn replaces H in HCl to produce SnCl₂.

Therefore, the reaction is a single replacement reaction.

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What is the limiting reactant when 20g CH4 react with 15g H20?
Art [367]

Answer:

H₂O.

Explanation:

  • It is clear from the balanced equation:

<em>CH₄ + 2H₂O → CO₂ + 4H₂.</em>

that 1.0  mole of CH₄ reacts with 2.0 moles of H₂O to produce 1.0 mole of CO₂ and 4.0 moles of H₂.

  • To determine the limiting reactant, we should calculate the no. of moles of (20 g) CH₄ and (15 g) H₂O using the relation:

<em>n = mass/molar mass</em>

<em></em>

no. of moles of CH₄ = mass/molar mass = (20 g)/(16 g/mol) = 1.25 mol.

no. of moles of H₂O = mass/molar mass = (15 g)/(18 g/mol) = 0.833 mol.

  • <em>from the balanced reaction, 1.0  mole of CH₄ reacts with 2.0 moles of H₂O.</em>

So, from the calculated no. of moles: 0.4167 mole of CH₄ reacts completely with 0.833 mole of H₂O and the remaining of CH₄ will be in excess.

<u><em>So, the limiting reactant is H₂O.</em></u>

4 0
2 years ago
Match the term with its correct charge. Positive charge. Negative charge. Neutral: No electric charge. A. electron B. neutron C.
Roman55 [17]

negative charge is electron

positive charge is a proton

no charge is neutron

4 0
3 years ago
According to the Kinetic Molecular Theory, as the volume of a gas increases: the number of particle impacts per unit area increa
aliya0001 [1]

As the volume of a gas increases <em>at constant temperature</em>, the number of particle impacts per unit area decreases.

There is the same number of impacts, but they are spread over a larger surface area.

Thus, the number of impacts per unit area decreases.

7 0
3 years ago
Read 2 more answers
1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride ? atoms of boron.
maks197457 [2]

Answer:

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.

2. How many MOLES of fluorine are present in  of boron trifluoride? moles of fluorine.​

Explanation:

The molecular formula of boron trifluoride is BF_3.

So, one mole of boron trifluoride has one mole of boron atoms.

1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.

The number of atoms in 2.20 moles of boron is:

One mole of boron has ---- 6.023x10^2^3 atoms.

Then, 2.20 moles of boron has

-=2.20 mol. x 6.023 x 10^2^3 atoms /1 mol\\=13.25x10^2^3 atoms

2. Calculate the number of moles of BF3 in 5.35*1022 molecules.

(5.35x10^2^2 molecules/6.023x10^2^3)x 1mol\\=0.0888mol

One mole of boron trifluoride has three moles of fluorine atoms.

Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.

=0.266mol of fluorine atoms.

5 0
2 years ago
Consider a reactant with an order of 1: What effect does that reactant have on the rate equation when the concentration is doubl
____ [38]

Answer:

1) The reaction rate is double with respect to that reactant

Explanation:

Hello,

By considering the rate law:

-r_A=kC_A

If we double the reactant A concentration, by definition, the rate will be doubled as well since the C_A power is one (order 1), this could be proved just by checking it out in the rate law.

Best regards.

6 0
3 years ago
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