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schepotkina [342]
2 years ago
11

Elements in the same period have _____.

Chemistry
2 answers:
faust18 [17]2 years ago
4 0

Ans: Elements in the same period have the same number of electron shells.

Svetllana [295]2 years ago
4 0
It would be 2 -the same number of electrons shells
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C12H7Cl3FNaO2 what are them elements in that chemical formula
LuckyWell [14K]
Assuming you are asking for the names of the elements in that formula , the answer is

carbon
hydrogen
chlorine
fluorine
sodium
oxygen
8 0
3 years ago
How can you distinguish between a solution, colloid, and suspension?
RSB [31]

Answer:

solution is clear solution while colloidal is between the solution and suspension. And in suspension particles are suspended.

Explanation:

In solution light can be passed without any scattering of light from solute particles while suspension is cloudy and having larger particle size than colloids, if suspension stands for a while particles will settle down easily.

In colloids light  will scattered and dispersed by reflecting with large particles.

3 0
3 years ago
Which chemical formula shows two atoms of iron (Fe) and three atoms of oxygen (O)?
Taya2010 [7]
Fe  O
 2    3 is what i would put
5 0
2 years ago
How many protons, neutrons, and electrons does gold have? I need to know how many protons, neutrons, and electrons the element g
zhuklara [117]
Protons: 79
neutrons: 118
electrons: 79
4 0
3 years ago
5. A beam of photons with a minimum energy of 222 kJ/mol can eject electrons from a potassium surface. Estimate the range of wav
torisob [31]

Answer: The range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

Explanation:

Given: 222 kJ/mol (1 kJ = 1000 J) = 222000 J

Formula used is as follows.

E = \frac{hc}{\lambda}

where,

E = energy

h = Planck's constant = 6.625 \times 10^{-25} Js

c = speed of light = 3 \times 10^{8} m/s

Substitute the values into above formula as follows.

E = \frac{hc}{\lambda}\\222000 J = \frac{6.625  \times 10^{-34}Js \times 3 \times 10^{8} m/s}{\lambda}\\\lambda = 8.953 \times 10^{21} m

Thus, we can conclude that the range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

7 0
3 years ago
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