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scoray [572]
3 years ago
10

Draw a shape using a rectangle and a triangle

Mathematics
1 answer:
navik [9.2K]3 years ago
7 0
You can draw a house :)
You might be interested in
Simplify the expression. -14 x 8 x 1/4 + (-22)
pochemuha
<span>-14 x 8 x 1/4 + (-22)

Apply BODMAS

Open the brackets:
</span>-14 x 8 x 1/4 + (-22) = <span>-14 x 8 x 1/4 -22

Division
-14 x 8 x (1/4) - 22 = </span><span>-14 x 8 x 0.25 - 22
</span><span>
Multiplication
</span><span>(-14 x 8 x 0.25 )- 22 = -28 - 22
</span><span>
Subtraction
-28-22 = -50

Correct answer: A <-50>




</span>
8 0
3 years ago
&lt;
ratelena [41]

For the first interval (-1, 2), f(-1) = f(2), which means that the average rate of change on that interval is zero, so the correct option is A.

<h3>Over which interval the rate of change is zero?</h3>

For a function f(x) we define the average rate of change over the interval (a, b) is defined as:

R = (f(b) - f(a))/(b - a)

Here the function is:

f(x) = x^2 - x  -1

And the rate of change will be zero on an interval (a, b) if and only if:

f(b) = f(a).

Notice that the first interval is (-1, 2)

f(-1) = (-1)^2 - (-1) - 1 = 1 + 1 - 1 = 1

f(2) = 2^2 - 2 - 1 = 4 - 2 - 1  =1

Then f(-1) = f(2), which means that the average rate of change on that interval is zero, so the correct option is A.

If you want to learn more about average rate of change:

brainly.com/question/23483858

#SPJ1

4 0
2 years ago
Solve the equation |4m| − 5 = 11.
Leno4ka [110]

Answer:

Please refer to the attachment

6 0
2 years ago
Which expression is equivalent to 4.8 – 2.2w + 1.4w – 2.4 ?
Vlad1618 [11]

Answer:

B) 0.4 (6 - 2w)

Step-by-step explanation:

You can only add or subtract with the numbers that have the same variable:

You can only add -2.2w and 1.4w

Which is -0.8w

Then add 4.8 and -2.4

Which is 2.4

Now the equation is -0.8w+2.4 or 2.4-0.8w

0.4 times 6 is 2.4

0.4 times 2w is -0.8w

Which is the same

-0.8w+2.4 or 2.4-0.8w

Hope this helps!

6 0
2 years ago
What is the solution of the system?
Kryger [21]
Greetings!

Solve the System, using Elimination:
\left \{ {{4x+2y=18} \atop {2x+3y=15}} \right.

Multiply Equation #2 by 2:
\left \{ {{4x+2y=18} \atop {2(2x+3y)=2(15)}} \right.

\left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.

Eliminate variable x:
-\frac{ \left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.}{0x-4y=-12}

4y=-12

Divide both sides by 4:
\frac{4y}{4}= \frac{12}{4}

y=3

Input this value into one of the Equations: 
4x+2y=18

4x+2(3)=18

Simplify:
4x+6=18

(4x+6)+(-6)=(18)+(-6)

4x=12

Divide both sides by 4.
\frac{4x}{4}= \frac{12}{4}

x=3

The Solution to this System (The Point of Intersection):
\boxed{(3,3)}

I hope this helped!
-Benjamin
7 0
3 years ago
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