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scoray [572]
3 years ago
10

Draw a shape using a rectangle and a triangle

Mathematics
1 answer:
navik [9.2K]3 years ago
7 0
You can draw a house :)
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Luz catches 83% of the balls in the outfield. What fraction of the balls does she not catch?
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17/100

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(a^(-5)b^(7)c^(3))^(2)-:(a^(4)b^(-2)c^(2))^(3) What are the powers of a b and c
Marina CMI [18]

Answer:

The powers of a,b and c for the given expression

\frac{(a^{-5}b^7c^3)^2}{(a^4b^{-2}c^2)^3}=a^{-22}b^{20}c^0} is -22,20 and 0 respectively

Step-by-step explanation:

Given expression is  \frac{(a^{-5}b^7c^3)^2}{(a^4b^{-2}c^2)^3}

To find the powers of a,b and c:

\frac{(a^{-5}b^7c^3)^2}{(a^4b^{-2}c^2)^3}=\frac{(a^{-5})^2(b^7)^2(c^3)^2}{(a^4)^3(b^{-2})^3(c^2)^3} ( using the property (ab)^m=a^m.b^m )

=\frac{a^{-10}b^{14}c^6}{a^{12}b^{-6}c^6} ( using the property (a^m)^n=a^{mn} )

=a^{-10}b^{14}c^6.a^{-12}b^{6}c^{-6} ( using the property \frac{1}{a^m}=a^{-m} )

=a^{-10-12}b^{14+6}c^{6-6} ( using the property a^m.a^n=a^{m+n} )

=a^{-22}b^{20}c^{0}

Therefore\frac{(a^{-5}b^7c^3)^2}{(a^4b^{-2}c^2)^3}=a^{-22}b^{20}c^{0}

The powers of a,b and c for the given expression

\frac{(a^{-5}b^7c^3)^2}{(a^4b^{-2}c^2)^3}=a^{-22}b^{20}c^0} is -22,20 and 0 respectively

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3 years ago
Find the value of the variable in the parallelogram.
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RZ= RZ over 4 -2
SW= SW over 9 + 11 over 9
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2 years ago
HURRY!!!!!!!!!! DUE SOON!!!!!!!!!!!!!!!!!!!!!!!!!
CaHeK987 [17]

Answer: don’t understand, maybe more like detail

Step-by-step explanation:

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