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iVinArrow [24]
3 years ago
12

Suppose the maximum safe average intensity of microwaves for human exposure is taken to be 1.50 W/m2. If a radar unit leaks 10.0

W of microwaves (other than those sent by its antenna) uniformly in all directions, how far away must you be to be exposed to an average intensity considered to be safe? Assume that the power spreads uniformly over the area of a sphere with no complications from absorption or reflection.
Physics
1 answer:
sp2606 [1]3 years ago
7 0

Answer:

  r = 0.728 m

Explanation:

The intensity is defined as the ratio between the power per unit area

       I = P / A

Where A is the area of ​​the sphere where the wave is

      A = 4π r²

In this exercise we are given the power of the P = 10.0 W micro waves, the safe intensity    I₁ = 1.5 W / m²

      A₁ = P / I₁

Calculate      

      A₁ = 10.0 / 1.5

     A₁ = 6.6667 m²

Let's clear the radius of the sphere

      r = √ A / 4π

      r = √ (6.6667 / 4π)

      r = 0.728 m

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Suppose I create a two-slit interference pattern using light with some wavelength lambda and slits with some separation D. If I
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Answer:

The pattern would spread out.

Explanation:

The fringe  width is given by the relation

fringe width = λ L / D where λ is wavelength of light used, L is distance of wall from the source of light and D is slit separation.

If we increase λ , fringe width will increase and therefore pattern will spread out .

7 0
4 years ago
The gravitational force between Earth and the Sun is a two-way force. Both the planet and the Sun attract each other. However, E
Ymorist [56]

The correct choice would be

B) The Sun’s mass is much greater than Earth’s

The sun as we know has greatest mass in our solar system and lighter objects tends to orbit around the heavier objects. the mass of earth is very much smaller as compared to that of the sun. hence the earth orbits around the sun due to the force of gravitational attraction between the two objects.

8 0
3 years ago
Read 2 more answers
If a 100-n net force acts upon a 50g car, what will the acceleration of the car be
Brrunno [24]

Answer:

2m/s

Explanation:

The formula for acceleration can be found by [ a = f/m ]

We are given the force [ 100N ] and the mass [ 50g ].

We can use these values to solve for the acceleration.

a = 100/50

a = 2m/s

Best of Luck!

3 0
3 years ago
A 1.6-lb collar is attached to a spring and slides without friction along a circular rod in a vertical plane. The spring has an
romanna [79]

Answer:

k = 652 lb/ft

Explanation:

Given :

Weight of the collar = 1.6 lb

The upstretched length of the spring = 6 in

Speed  = 16 ft/s

PA = 8 + 10

     = 18 inch

Let the initial elongation be $\Delta x_i$

∴ $\Delta x_i$ = 18 - 6

         = 12 inch = 1 foot

$PB = \sqrt{13^2+5^2}$

      = 13.925 inch

Final elongation in the spring

$\Delta x_B = 7.928 $ inch = 0.66 feet

Applying the conservation of the mechanical energy between A and B is

$K.E_A+P.E_{g,A}+P.E_{sp,A}= K.E_B+P.E_{g,B}+P.E_{sp,B} $

$0+mg_r+\frac{1}{2}k(\Delta x_i)^2=\frac{1}{2}mv_B^2+0+\frac{1}{2}k(\Delta x_B)^2$

$\frac{1}{2}k[(1)^2-(0.66)^2]=\frac{1.6}{2}\times (16)^2-1.6 \times 32 \times \frac{5}{12}$

0.281 \ k =204.8-21.33

k = 652 lb/ft

5 0
3 years ago
If you weigh 150 lbs. on the surface of Earth, how much would you weigh on Venus? On Mars?
Ghella [55]

Answer:

weight on Venus =  604.15 N

weight on Venus = 252.01 N

Explanation:

Given:

Weight on the earth , W = 150 lbs

now,

1 lbs = 4.45 N

thus,

W = 150 × 4.45  = 667.5 N

now, mass on the earth, m = 667.5/9.8 = 68.11 kg

now,

⇒ weight on Venus,

the acceleration due to   gravity on venus = 8.87 m/s²

thus,

weight on Venus = mass × acceleration due to   gravity on venus

or

weight on Venus = 68.11 × 8.87 = 604.15 N

⇒ weight on mars,

the acceleration due to   gravity on mars = 3.70 m/s²

thus,

weight on Venus = mass × acceleration due to   gravity on venus

or

weight on Venus = 68.11 × 3.70 = 252.01 N

7 0
4 years ago
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