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xenn [34]
3 years ago
9

A mass of 0.8 kg is fixed at a vertical spring with an unknown spring constant. When spring is released from rest, it extends to

15cm before it stops. As the system oscillates with Simple Harmonic Motion (SHM) the weight is pulled down 20cm further downward and being released.
1. What is the spring constant?
2. What is the total energy of the system?
3. What is the angular frequency of spring?
4. What is the velocity of the system at x=10cm below equilibrium position? ​
Physics
1 answer:
Delicious77 [7]3 years ago
4 0

Answer:

1) k = 52 N/m

2) E = 1.0 J

3) ω = 8.1 rad/s

4) v = 1.4 m/s

Though asked for a velocity, we can only supply magnitude (speed) because we don't have enough information to determine direction.

If it happens to be the first time it is at y = - 10 cm after release, the velocity is upward.

Explanation:

Assuming the initial setup is after all transients are eliminated.

kx = mg

k = mg/x = 0.8(9.8) / 0.15

k = 52.26666.... ≈ 52 N/m

E = ½kA² = ½(52)(0.20²) = 1.045333... ≈ 1.0 J

ω = √(k/m) = √(52 / 0.8) = 8.0829... ≈ 8.1 rad/s

½mv² = ½kA² - ½kx²

v = √(k(A² - x²)/m) = √(52(0.20² - 0.10²)/0.8) = 1.39999... ≈ 1.4 m/s

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A lightbulb marked "75 W [at] 120 V" is screwed into a socket at one end of a long extension cord, in which each of the two cond
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Answer:

Part c)

P = 73.8 Watt

Explanation:

Light bulb is marked as 75 W and 120 Volts

so it means that when we apply 120 volts across the bulb then it will consume the total power of 75 W

now when we connected the bulb with the help of conducting wires with some resistance across them then few of its voltage will fall across the wires

due to which the voltage across bulb is less than 120 Volts

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Part c)

Resistance of the bulb is given as

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R = \frac{120^2}{75}

R = 192 ohm

now total resistance of the circuit

R_{net} = 192 + 0.8 + 0.8

now current in the circuit

i = \frac{120}{193.6}

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so actual power delivered to the bulb is given as

P = i^2 R

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5 0
4 years ago
The block slides on a horizontal frictionless surface. The block has a mass of 1.0kg and is pushed 5.0N at 45°. What is the magn
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Using trigonometry to find the horizontal component of the force:

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Use this horizontal component of the force to solve for for the acceleration of the object:

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given data

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G = 6.67 × 10^{-11} Nm²/kg²

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radius of its orbit

solution

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