A center-seeking force related to acceleration is _______ force.
1 answer:
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Answer:
t = 4 s
Explanation:
As we know that the particle A starts from Rest with constant acceleration
So the distance moved by the particle in given time "t"
Now we know that B moves with constant speed so in the same time B will move to another distance
now we know that B is already 349 cm down the track
so if A and B will meet after time "t"
then in that case
on solving above kinematics equation we have
Answer:
Total work done is 2606.08 J.
Explanation:
Given :
Mass of box , m = 23 kg .
Force applied , F = 100 N .
Angle from horizon , .
Coefficient of kinetic friction , .
Distance travelled by box , d = 34 m .
Now ,
Total work done = work done by boy + work done by friction.
Hence , this is the required solution.