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Brut [27]
4 years ago
5

An unknown, clear liquid is given to you in a beaker. You transfer some of the liquid from the beaker to a clean, empty test tub

e, and begin to heat it. Soon, you observe a vapour leaving the top of the test tube. With further analysis you discover that the vapour is water vapour. Eventually, all that's left are a few crystals stuck to the sides of the test tube. Was the original liquid an element, a compound, or a mixture? Explain
Chemistry
2 answers:
shutvik [7]4 years ago
8 0
<span>A mixture because there was remaining  left at the bottom of the test tube and another substance that evaporated meaning that there was a lot more than one thing in the tube </span>
slavikrds [6]4 years ago
7 0
A mixture because there was residue left at the bottom of the test tube and another substance that evaporated meaning that there was more than one thing in the test tube.
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Surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

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So therefore, surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

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5 0
1 year ago
Calculate the formula mass of calcium iodate, ca(io3)2, in atomic mass units (amu or u).
VARVARA [1.3K]
<span>389.88094 amu First we look up the atomic mass of all elements contained in calcium iodate using the periodic table: Ca: 40.078 I: 126.90447 O: 15.999 As an intermediate step we calculate the molecular mass of the ion IO3: 126.90447 + 3*15.999 = 174.90147 Then we calculate the mass of one calcium atom and 2 iodate ions: 2*174.90147 + 40.078 = 389.88094 amu</span>
7 0
3 years ago
If you were asked to run Spartan calculations on the C2H3O2-/H3O ion pair, the trend in the resulting data points would appear s
Taya2010 [7]

Answer:

a. True

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4 0
3 years ago
 how do electrons behave when metals react with non-metals
Tems11 [23]
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4 0
4 years ago
I will love u forever if u help me + branliest
Elenna [48]

Answer:

mass \: of \: mgo \:  = 20grams \\ mass \: of \: mg \:  = 15grams \\ so \: from \: the \: law \: of \: conservation \: of \: mass \:  = mass \: of \: o2 = (20 - 15)grams \:   \\ = 5grams(ans)

Hope it helps

4 0
3 years ago
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