Answer:
75.37 g
Explanation:
From the question given above, the following data were obtained:
Percentage of nitrogen (N) in the compound = 36.86 %
Mass of nitrogen (N) in the compound = 44 g
Mass of oxygen (O) in the compound =?
Next, we shall determine the total mass of the compound. This can be obtained as follow:
Percentage of nitrogen (N) in the compound = 36.86 %
Mass of nitrogen (N) in the compound = 44 g
Total mass of compound (T) =?
Percentage of N = mass of N/ total mass × 100
36.86 % = 44 / T
36.86 / 100 = 44 / T
Cross multiply
36.86 × T = 100 × 44
36.86 × T = 4400
Divide both side by 36.86
T = 4400 / 36.86
Total mass = 119.37 g
Next, we shall determine the percentage of oxygen in the compound. This can be obtained as follow:
Percentage of N = 36.86 %
Percentage of O =?
Percentage of O = 100 – 36.86 %
Percentage of O = 63.14 %
Finally, we shall determine the mass of oxygen in the compound. This can be obtained as follow:
Percentage of O = 63.14 %
Total mass = 119.37 g
Mass of O =.?
Percentage of O = mass of O / total mass × 100
63.14 % = Mass of O / 119.37
Cross multiply
Mass of O = 63.14 % × 119.37
Mass of O = (63.14 / 100)× 119.37
Mass of O = 75.37 g
Thus, the mass of oxygen in the compound is 75.37 g
