<span>number Moles of C = 54.5 g / 12.011 = 4.54
number Moles of H = 9.10 / 1.008 = 9.02
number Moles of O = 36.4 / 16 = 2.28
if we want to divide by the smallest number
4.54 / 2.28 = 2 => C
9.02 / 2.28 = 4 => H
2.28 / 2.28 = 1 => O
Empirical formula will be = C2H4O</span>
Answer: The density of Ammonia is 0.648 g/l
Explanation:
Density = Mass/ Volume
Mass of one mole of Ammonia (NH3) = 17.031g
Volume =?
Using the ideal gas law we can determine the volume.
PV = nRT
P = 0.913 atm, V= ?, n = 1, R = 0.08206 L.atm/K, and T= 293K
Make V the subject of the formular, we then have;
V= nRT/ P = 1 mol x 0.08206 L.atm/ K.mol x 293 / 0.913 atm
V = 24.04358/ 0.913 = 26.3L
Having gotten the value of Volume in this question, we then go back to solve for density.
Density = Mass/ Volume
17.031g/ 26.3L = 0.64756 ≈ 0.648 g/l
Yes, that is true. in order for it to be a redox reaction, both oxidation and reduction must be occurring.
Answer:
The formula for pressure is P = F/A, in which P is pressure, F is force, and A is area.
Explanation:
Answer:-
People with diabetes must monitor their blood glucose levels constantly.
Blood glucose levels are nowadays measured by the help of enzyme glucose oxidase. The enzyme glucose oxidase catalyzes the oxidation of glucose to gluconic acid.
By this way all of the glucose is measured at one time. At the same time hydrogen peroxide is produced.
The hydrogen peroxide reacts with a second color producing chemical. The concentration of the glucose can be related to the intensity of color produced
