People have died over drinking big amounts of water in fraternity initiations and while they where having the radio contest. So no there it's no life after hydration
Answer:
CH2O
Explanation:
Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.
C = 5.692/14.229 * 100 = 40%
O = 7.582/14.229 * 100 = 53.29%
H = 0.955/14.229 * 100 = 6.71%
We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.
C = 40/12 = 3.333
O = 53.29/16 = 3.33
H = 6.71/2 = 6.71
Dividing by the smaller value which is 3.33
C = 3.33/3.33 = 1
O = 3.33/3.33= 1
H = 6.71/3.33 = 2
The empirical formula of the compound ribose is CH2O
So, if 1 mole occupies 22.4 L, the imediate conclusion is that a bigger number of moles will occupy more than 22.4 L, and a smaller number of moles will occupy less than 22.4 L. In your case, 3 moles of gas will occupy 3 times more volume than 1 mole of gas
no need to show work i am a teacher at a college
Answer:
15.89%
Explanation:
To calculate the percentage of carbon in BeC2O4•3H2O, first we calculate the molar mass of BeC2O4•3H2O
MM of BeC2O4•3H2O = 9+(12x2)+(4x16)+3(2+16) = 9+24+64+54 =151g/mol
Mass of C in BeC2O4•3H2O = 2x12 = 24g
%Mass of carbon in BeC2O4•3H2O = (24/151) x 100
= 15.89%
Answer: option A
Explanation: Organic chemistry deals with the study of carbon and hydrogen containing compounds, drugs and pharmaceuticals etc.
