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Ratling [72]
3 years ago
13

If a light bulb is missing or Broken in a parallel circuit,will the other bulb light

Chemistry
1 answer:
umka2103 [35]3 years ago
5 0
Yes, if it’s a parallel circuit the wires are two different wires so it will light because that bulb isn’t connected to the one that went out
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If you make a solution using 1.0 mol KBr in 1.0 kg water, how will the vapor pressure of this solution compare to the vapor pres
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Answer:

it will be twice as large

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3 years ago
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Which of the following is a product of aerobic respiration?
sasho [114]

Answer:

The product of aerobic respiration is Carbon dioxide.

Explanation:

  • The process of breaking down glucose to produce energy and waste products is called respiration. Livings beings need respiration process to generate energy so  that they can survive.
  • The types of respiration are : Anaerobic and aerobic respiration.
  • Aerobic respiration takes place in presence of oxygen and produces large amount of energy.
  • The final product of aerobic respiration are carbon dioxide, water and 38 ATP of energy.
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4 years ago
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A sample of solid sodium hydroxide, weighing 13.20 grams is dissolved in deionized water to make a solution. What volume in mL o
Andreas93 [3]
<h3>Answer:</h3>

2.809 L of H₂SO₄

<h3>Explanation:</h3>

Concept tested: Moles and Molarity

In this case we are give;

Mass of solid sodium hydroxide as 13.20 g

Molarity of H₂SO₄ as 0.235 M

We are required to determine the volume of H₂SO₄ required

<h3>First: We need to write the balanced equation for the reaction.</h3>
  • The reaction between NaOH and H₂SO₄ is a neutralization reaction.
  • The balanced equation for the reaction is;

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

<h3>Second: We calculate the umber of moles of NaOH used </h3>
  • Number of moles = Mass ÷ Molar mass
  • Molar mass of NaOH is 40.0 g/mol
  • Therefore;

Moles of NaOH = 13.20 g ÷ 40.0 g/mol

                          = 0.33 moles

<h3>Third: Determine the number of moles of the acid, H₂SO₄</h3>
  • From the equation, 2 moles of NaOH reacts with 1 mole of H₂SO₄
  • Therefore, the mole ratio of NaOH: H₂SO₄ is 2 : 1.
  • Thus, Moles of H₂SO₄ = moles of NaOH × 2

                                    = 0.33 moles × 2

                                   = 0.66 moles of H₂SO₄

<h3>Fourth: Determine the Volume of the acid, H₂SO₄ used</h3>
  • When given the molarity of an acid and the number of moles we can calculate the volume of the acid.
  • That is; Volume = Number of moles ÷ Molarity

In this case;

Volume of the acid = 0.66 moles ÷ 0.235 M

                                = 2.809 L

Therefore, the volume of the acid required to neutralize the base,NaOH is 2.809 L.

7 0
4 years ago
What is the temperature of a water body containing a 90% saturation and 11.5 ppm of dissolved oxygen?
ozzi
Using the chart that has been provided, we may determine water temperature. We do this by drawing a straight line form the bottom scale which has the ppm of oxygen dissolved to the middle scale which has the percentage saturation.

The line starts from 11.5 ppm on the bottom scale and goes to 90% on the middle scale. Next, we continue this line, without changing its slope, to the third scale showing temperature. We see that it crosses the temperature scale at 4°C.

The temperature of the water is 4 °C.
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4 years ago
Unscramble dreor to get a science answer
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Order. 
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