2 years ago

What’s the answer ?

Mathematics

1 answer:

svlad2 [7]2 years ago

7 0

Answer:

Step-by-step explanation:

lining them up:

19, 19, 22, 25, 27, 31, 32, 32, 40

We can see that 27 is in the middle when h is 40

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Find the solution of the following system of equations -5+2y=9 3x+5y=7

Rudiy27

Answer:

$x=-\frac{28}{3}\\\\y=7$

Step-by-step explanation:

Given the system of equations:

$\left \{ {{-5+2y=9} \atop {3x+5y=7}} \right.$

You can pply Substitution method:

First you must solve for "y" from the first equation:

$-5+2y=9\\\\2y=9+5\\\\2y=14\\\\y=\frac{14}{2}\\\\y=7$

Therefore, the second and final step to solve the system of equations is to substitute the value of "y" into the second equation and solve for "x":

$3x+5(7)=7\\3x=7-35\\\\x=-\frac{28}{3}$

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Step-by-step explanation:

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I believe it's 5,6

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10. For the equation 3x – 4 = 8, which

irga5000 [103]

Answer:

x = 4

Step-by-step explanation:

We can find the answer to this by solving the equation:

3x - 4 = 8

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If f(x) = kx^3+ x^2 − kx + 2, find a number k such that the graph of f contains the point (k, -10)

Elina [12.6K]

If we write $k$ where we see $x$ in the equation and set the result equal to $-10$ , we get the result.

$f(k)=k(k)^3+k^2-k(k)+2$
$=k^4+k^2-k^2+2$
$=k^4+2=-10$
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$k_{1}=\sqrt[4]{3}(-1-i)$
$k_{2}=\sqrt[4]{3}(-1+i)$
$k_{3}=\sqrt[4]{3}(1-i)$
$k_{4}=\sqrt[4]{3}(1+i)$

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7 months ago