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3 years ago

The height of a sunflower increases from 82 cm to 1 metre in a week. Find the percentage increase in height.

1 answer:

7 0

So, the sunflower is increasing from .82 meters to 1 meter. This is a .18 meter increase. We need to figure out what percent of 82 18 is. We do this by dividing 18 by 82 and multiply the result by 100 to get a percent. This equals 21.95%

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AD=3, BD=5, AE=4. Find CE

EastWind [94]

Answer:

6.6

Step-by-step explanation:

Triangles ADE and ABC are similar.

Therefore,

AD/AB=AE/AC

3/8=4/AC

3AC=32

AC=10.6(3 s.f)

CE=10.6-4=6.6

5 0

2 years ago

5 - 3(6 - 2y)

saul85 [17]

Answer:

6y - 13

Step-by-step explanation:

5 - 3(6 - 2y)

Distribute;

5 - 18 + 6y

-13 + 6y <em>OR</em> 6y - 13

6 0

3 years ago

Read 2 more answers

Is 4/5 bigger than 0.75

hjlf

4/5 is greater than 0.75. That is because, if you turn 4/5 into a decimal, them that decimal will be equal to 80/100. 0.75 is 75/100 as a fraction. 80/100 (4/5 simplified) compared to 75/100 is greater. The answer is yes.

5 0

3 years ago

Assume z = x + iy, then find a complex number z satisfying the given equation. d. 2z8 – 2z4 + 1 = 0

kodGreya [7K]

Answer: complex equations has n number of solutions, been n the equation degree. In this case:

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i11,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i101,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i191,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i281,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i78,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i168,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i258,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i348,75°}$

Step-by-step explanation:

I start with a variable substitution:

$Z^{4} = X$

Then:

$2X^{2}-2X+1=0$

Solving the quadratic equation:

$X_{1} =\frac{2+\sqrt{4-4*2*1} }{2*2} \\X_{2} =\frac{2-\sqrt{4-4*2*1} }{2*2}$

$X=\left \{ {{0,5+0,5i} \atop {0,5-0,5i}} \right.$

Replacing for the original variable:

$Z=\sqrt[4]{0,5+0,5i}$

or $Z=\sqrt[4]{0,5-0,5i}$

Remembering that complex numbers can be written as:

$Z=a+ib=|Z|e^{ic}$

Using this:

$Z=\left \{ {{{\frac{\sqrt{2}}{2} e^{i45°} } \atop {{\frac{\sqrt{2}}{2} e^{i-45°} }} \right.$

Solving for the modulus and the angle:

$Z=\left \{ {{\sqrt[4]{\frac{\sqrt{2}}{2} e^{i45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i45}} } \atop {\sqrt[4]{\frac{\sqrt{2}}{2} e^{i-45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i-45}} }} \right.$

The possible angle respond to:

$RAng_{12...n} =\frac{Ang +360*(i-1)}{n}$

Been "RAng" the resultant angle, "Ang" the original angle, "n" the degree of the root and "i" a value between 1 and "n"

In this case n=4 with 2 different angles: Ang = 45º and Ang = 315º

Obtaining 8 different angles, therefore 8 different solutions.

3 0

3 years ago

The temperature is currently 60 F. If the temperature drops on average 2 degrees per day, how many days will it be until the tem

Bezzdna [24]

9 days

because legit 60 - 42 = 18
18 divide 2 = 9 days

Or you could’ve just done 42 + 2 +2+2 until you get to 60 and you would do it 9 times. Meaning 9 days

8 0

2 years ago