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4 years ago

1 point

Physics

1 answer:

s2008m [1.1K]4 years ago

5 0

Answer:

The person has no displacement

Explanation:

The given parameters are

The location of the person = The equator

The distance covered in one revolution = Total distance around the body

The total distance around the Earth = The circumference of the Earth = 40.075 kilometres

The total distance moved by the person standing at the equator during the Earths complete revolution = 40,075 kilometres

The initial location of the person in relation to a fixed point in space outside Earth at the start of the revolution = x km

The final location of the person in relation to the fixed point in space outside Earth at the completion of the revolution = x km

The displacement = Change in position = Final location - Initial location

∴ The displacement = x km - x km = 0 km.

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For the chemical reaction below, determine the amount of hi produced when 3.35 g of hydrogen is reacted with 50.75 g of iodine t

ra1l [238]

Molar mass of H₂ = 1.008 × 2 g/mol = 2.016 g/mol 
Molar mass of I₂ = 126.9 × 2 g/mol = 253.8 g/mol 
Molar mass of HI = (1.008 + 126.9) g/mol = 127.9 g/mol

H₂(g) + I₂(g) → 2HI 
Mole ratio H₂ : I₂ : HI = 1 : 1 : 2 

Then the initial number of moles of H₂ = (3.35 g) / (2.016 g/mol) = 1.662 mol 
Initial number of moles of I₂ = (50.75 g) / (253.8 g/mol) = 0.2000 mol < 1.662 mol 
Hence, I₂ is the limiting reactant (limiting reagent). 

Number of moles of I₂ reacted = 0.2000 mol 
Number of moles of HI reacted = (0.2000 mol) × 2 = 0.4000 mol
Mass of HI reacted = (127.9 g/mol) × (0.4000 mol) = 51.16 g

8 0

4 years ago

A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second2. What is the net force on the car

Novay_Z [31]

Answer:

$4.5 *10^{3}\ kgm/s^{2}$

Explanation:

Given:

$Mass= 1.00 * 10^{3} \ kilograms,\\Acceleration =4.5\ meters/second^{2}$

As we know that

Force=Mass * Acceleration

Putting the value of mass and Acceleration we get ,

$Force\ = \ 1.00 * 10^{3} * 4.5\ m/s^{2}$

$Force\ =4.5 * \ 10^{3} \ kgm/s^{2}$

Therefore Net force is : $4.5 *10^{3}\ kgm/s^{2}$

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3 years ago

HELP PLS MARKING BRANLIST 100 Pts TAKING TEST RN

vredina [299]

Answer:

0.5 m/s2

Explanation:

accelration formula : final velocty - starting velocity divided by time

5 0

3 years ago

A 2.40 kgkg can of coffee moving at 1.50 m/sm/s in the +x+x-direction on a kitchen counter collides head-on with a 1.20 kgkg box

Monica [59]

Answer:

1.35 m/s in the +x direction

Explanation:

Mass of can of coffee, m = 2.4 kg

Initial velocity of can of coffee, u = 1.5 m/s

Mass of box of macaroni, M = 1.2 kg

Initial velocity of box of macaroni, U = 0 m/s

Final velocity of can of coffee, v = 0.825 m/s

We can find the final velocity of the box of macaroni, V, by using the Principle of Conservation of momentum:

Total initial momentum = Total final momentum

Momentum is given as the product of mass and velocity. Hence:

mu + MU = mv + MV

(2.4 * 1.5) + (1.2 * 0) = (2.4 * 0.825) + (1.2 * V)

3.6 + 0 = 1.98 + 1.2V

1.2V = 3.6 - 1.98 = 1.62

=> V = 1.62/1.2

V = 1.35 m/s

The final velocity of the box of macaroni is 1.35 m/s and it is in the +x direction.

3 0

3 years ago

What was his average swimming speed during the second half of the race if he tied the record, which was at an average speed of 2

Nimfa-mama [501]

I believe this question has additional detail which stated that during the 1st half, his speed was 2.01 m/s. From this we can calculate his speed during the second half, v2, using the formula:

v_ave = (v1 + v2) / 2

2.05 m/s = (2.01 m/s + v2) / 2

v2 = 2.09 m/s

4 0

3 years ago