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Black_prince [1.1K]
2 years ago
12

A teacher pushed a 98 newton desk across a floor for a distance of 5 meters. He exerted a horizontal force of 20 N for four seco

nds. What was his power?
Physics
1 answer:
Pie2 years ago
7 0

Answer:

First let's find the work.

Work = Force*Displacement

= 20*5

= 100 Joules

Power = Work/Time

= 100/4

= 25 Watts

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You use 350 W of power to move a 7.0 N object 5 m.<br> How long did it take?
PilotLPTM [1.2K]

Answer:

0.1 second

Explanation:

We are given;

Power; P = 350 W

Force; F = 7 N

Distance; d = 5 m

Formula for power is;

P = workdone/time taken

Workdone = F × d

Thus;

350 = (7 × 5)/t

t = 35/350

t = 0.1 second

4 0
3 years ago
MAJOR POINTS! Solve the system of equations to find <img src="https://tex.z-dn.net/?f=%20a_%7B2%7D%20%20" id="TexFormula1" title
Monica [59]
You are dealing with pulleys?

can be done with addition of the two equations to eliminate T.

(2^{*}) \quad {} -m_1 g \cos \theta + T = m_1 a _2
+
(4^{*}) \quad 3m_1 g - T = 3m_1 a_2
=

(-m_1 g \cos\theta  +  3m_1 g) + (T - T) = m_1 a _2 + 3m_1 a_2 \implies \\ \\&#10;(-m_1 g \cos\theta  +  3m_1 g) = 4m_1 a_2 \implies \\ \\&#10;m_1(- g \cos\theta  +  3g)= 4m_1 a_2

we can cancel m₁ by dividing both sides by it, assuming mass is not zero


(- g \cos\theta + 3g)= 4a_2 \implies \\ \\&#10;a_2 = \dfrac{- g \cos\theta + 3g}{4} \\ \\&#10;a_2 = \dfrac{- 9.80  \cos 60 + 3(9.80)}{4} \\ \\&#10;a_2 = 6.125 \text{m/s}^2&#10;

a₂ = 6.125 m/s² ( do significant digits if you need to)
6 0
3 years ago
Prior Knowledge Questions (Do these BEFORE using the Gizmo.) Strings of holiday lights can be designed in one of two ways. In so
IgorLugansk [536]

Answer:

They would go out

Explanation:

This is because, in a series connection, the same current passes through each light. Since the current is the same, if one light burns out, it cuts off the rest of the other lights and thus, no current flows in the string again.

Whereas, in a parallel connection, each light is attached to its own wire and thus has a different current flowing through it than the rest of the other wires.  If one of the lights goes out, current stops flowing through it but, it doesn't affect the other lights.

8 0
2 years ago
Investigators are exploring ways to treat milk for longer shelf life by using pulsed electric fields to destroy bacterial contam
Georgia [21]

Answer:

C = 3.77*10⁻¹⁰ F = 377 pF

Q = 1.13*10⁻⁵ C

Explanation:

Given

D = 8.0 cm = 0.08 m

d = 0.95 cm = 0.95*10⁻² m

k = 80.4  (dielectric constant of the milk)

V = 30000 V

C = ?

Q = ?

We can get the capacitance of the system applying the formula

C = k*ε₀*A / d

where

ε₀ = 8.854*10⁻¹² F/m

and   A = π*D²/4 = π*(0.08 m)²/4

⇒  A = 0.00502655 m²

then

C = (80.4)*(8.854*10⁻¹² F/m)*(0.00502655 m²) / (0.95*10⁻² m)

⇒  C = 3.77*10⁻¹⁰ F = 377 pF

Now, we use the following equation in order to obtain the charge on each plate when they are fully charged

Q = C*V

⇒  Q = (3.77*10⁻¹⁰ F)*(30000 V)

⇒  Q = 1.13*10⁻⁵ C

7 0
3 years ago
I need help on this still stuck on it
jenyasd209 [6]
The underlined offset 2 is called a subscript and it describes how many of the element preceding it per molecule of the entire molecule/compound. In the case of H20, it means there are 2 Hydrogen per H20 molecule.
6 0
2 years ago
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