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mr Goodwill [35]
3 years ago
11

Which of the following statements is true? Communicable diseases cannot be transmitted by nonliving objects. Sexually transmitte

d diseases are spread by direct contact with bodily fluids. Gastrointestinal diseases are usually transmitted by infected water droplets in the air. The best prevention against communicable diseases is over-the-counter medication.
Physics
2 answers:
Lemur [1.5K]3 years ago
4 0

Answer:

Sexually transmitted diseases are spread by direct contact with bodily fluids.

Explanation:

if you have a disease you can give it to someone by having sex because your fluids go into or either combine

Zanzabum3 years ago
3 0

Answer:

B

Explanation:

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The force of the pulley is 652 newtons. It accelerates at 53 m/s. How much does the object weigh. a 1230 grams b 1.230 gram c 12
RoseWind [281]

Answer:

d. 12.30 grams

Explanation:

Given the following data;

Force = 652 N

Acceleration = 53 m/s²

To find how much the object weigh, we would need to determine its mass;

Force = mass * acceleration

652 = mass * 53

Mass = 652/53

<em>Mass = 12.30 grams.</em>

<em>Therefore, the object weighs 12.30 grams. </em>

5 0
3 years ago
Light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance li
Anastasy [175]

Answer: 3.142656 × 10^16 feet

Explanation: Given that the

Speed = 982,080,000 ft/s, and

Time = 32,000,000 seconds

The formula for speed is:

Speed = distance/ time

Make distance the subject of formula

Since the time is second in one year and speed is ft/s, substitute both into the formula

Distance = speed × time

distance = 982,080,000 × 32,000,000

Distance = 3.142656 × 10^16 feet.

The distance of one light year in feet is 3.142656 × 10^16

8 0
3 years ago
The maximum speed with which you can throw a stone is about 25 m/s. Can you hit a window 50 m away and 13 m up from the point wh
Nookie1986 [14]

Answer:

no, the maximum height = 12.3m

Explanation:

The equation for the trajectory of the ball for a given angle can be derived from:

(1) x=cos\phi v_0t

and

(2) y=-\frac{1}{2}gt^2 +sin\phi v_0t

Combining equation 1 and 2:

(3) y=xtan\phi -\frac{gx^2}{2cos^2\phi v_0^2}

Taking the derivative:

(4) \frac{dy}{d\phi}=\frac{xsec^2\phi}{v_0^2}(v_0^2-gxtan\phi)

Setting equation 4 equal to zero to calculate the maximum angle:

(5) \phi=tan^{-1}(\frac{v_0^2}{gx})

Plugging equation 5 back into equation2 confirms, the trajectory can't reach the target. The maximum height is 12.3m.

3 0
3 years ago
Read 2 more answers
A crate is given a quick push at the bottom of a loading ramp. The box slides up the ramp, and then slides back down. If there i
tamaranim1 [39]

Answer:

The slide back down takes longer than the slide up.

Explanation:

In this is problem, the loss of energy is a key factor.

When the box is pushed up the ramp, it gains a specific speed, and an associated kinetic energy<em>. </em>As it slides up, it losses kinetic energy due to the gravitational and frictional forces, and it is transformed to gravitational potential energy (or potential energy). When it reaches its highest point, the speed becomes cero and all its kinetic energy is converted to potential energy.

However, since there is a frictional force, some amount of energy is loss, so the potential energy is lesser than the initial kinetic energy.

The same occurs when the box slides back down: its potential energy is converted into kinetic energy, but some energy is loss due to the frictional force. This means that the final kinetic energy is smaller than the initial, which implies that its final velocity is smaller than the initial velocity.

Using the acceleration definition:

a=\frac{v_f-v_o}{t}

We solve for the time (t) and get:

t=\frac{v_f-v_o}{a}

We have to use this equation two times, one for each movement  (slide up and slide down).

The gravitational force points down with the same magnitude in both, but the frictional force goes down when the box is sliding up and it goes up when the box slides down. So the magnitude of the acceleration when it goes up is smaller than the other one.

If we analyze both situations:

A) When it goes up:

t_{up}=-\frac{v_o}{a_1}

B) When it goes down:

t_{down}=\frac{v_f}{a_2}

And we have that v_o>v_f and a_1. Which implies that, in any case, t_{up}>t_{down}.

6 0
3 years ago
What type of reaction occurs when you strike a match?
lyudmila [28]
The type of reaction is combustion 
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3 years ago
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