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Montano1993 [528]
3 years ago
14

The number 3 next to hydrogen in NH3 is the ____.

Chemistry
1 answer:
andrew-mc [135]3 years ago
4 0
Answer:

C. Subscript

Explanation:

The numbers appearing as subscripts in the chemical formula indicate the number of atoms of the element immediately before the subscript.
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How many moles (of molecules or formula units) are in each sample?
Alexus [3.1K]

The number of moles in each sample will be 0.391 moles, 30.7 moles, 0.456 moles, and 1350 moles

<h3>What is the number of moles?</h3>

The number of moles of a substance is the ratio of the mass of the substance to the molar mass.

In other words; mole = mass/molar mass.

Thus:

  • moles of 18.0 g NO_2 = 18.0/46

                                   = 0.391 moles

  • moles of 1.35 kg CO_2 = 1350/44

                                         = 30.7 moles

  • moles of 46.1 g KNO_3 = 46.1/101.1

                                          = 0.456 moles

  • moles of 191.8 kg Na_2SO_4 = 191800/142

                                                 = 1350 moles

More on the number of moles of substances can be found here: brainly.com/question/1445383

#SPJ1

5 0
2 years ago
A 44.0 g sample of an unknown metal at 99.0 oC was placed in a constant-pressure calorimeter of negligible heat capacity contain
tatiyna

Answer:

C_m=0.474\frac{J}{g\°C}

Explanation:

Hello.

In this case, since this is a system in which the water is heated up and the metal is cooled down in a calorimeter which is not affected by the heat lose-gain process, we can infer that the heat lost by the metal is gained be water, it means that we can write:

Q_m=-Q_w

Thus, in terms of masses, specific heats and temperatures we can write:

m_mC_m(T_{eq}-T_m)=-m_wC_w(T_{eq}-T_w)

Whereas the equilibrium temperature is the given final temperature of 28.4 °C and we can compute the specific heat of the metal as shown below:

C_m=\frac{-m_wC_w(T_{eq}-T_w)}{m_m(T_{eq}-T_m)}

Plugging the values in and since the density of water is 1.00 g/mL so the mass is 80.0g, we obtain:

C_m=\frac{-80.0g*4.184\frac{J}{g\°C} (28.4\°C-24.0\°C)}{44.0g(28.4\°C-99.0\°C)}\\\\C_m=0.474\frac{J}{g\°C}

Best regards!

6 0
2 years ago
0.000068 g Express your answer as an integer.
ivann1987 [24]
6.8x10^5? Scientific notation
5 0
3 years ago
Read 2 more answers
A voltaic cell is constructed from an Ni2+(aq)−Ni(s)Ni2+(aq)−Ni(s) half-cell and an Ag+(aq)−Ag(s)Ag+(aq)−Ag(s) half-cell. The in
eduard

Answer:

+1.03 V

Explanation:

The standard emf of the voltaic cell is the value of the standard potential of it, which is calculated by the standard reduction potential (E°).

The standard reduction potential is the potential needed for the reduction reaction happen, and it's determined by the reaction with the hydrogen cell (which has E° = 0.0V). The half-reactions of reduction of Ni⁺² and Ag⁺, are:

Ni⁺²(aq) + 2e⁻ → Ni(s) E° = -0.23 V

Ag⁺(aq) + e⁻ → Ag(s) E° = +0.80 V

The value is calculated by a spontaneous reaction, in which the cell with the greater E° is reduced (gain electrons), and the other is oxidized (loses electrons). So, Ag⁺ reduces.

emf = E°reduces - E°oxides

emf = 0.80 - (-0.23)

emf = +1.03 V

8 0
3 years ago
In a redox reaction what happens to a substance's charge when it is oxidized
Temka [501]
<span>oxidizing substance removes electrons from another substance, which are then added to itself, the oxidizing substance becomes “reduced” (more negative). And because it “accepts” electrons .</span>
5 0
3 years ago
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