Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Ca2+, V5+, Br- , S2-
1 answer:
Answer:
CaS, CaBr₂, VBr₅, and V₂S₅.
Explanation:
The ionic compound should be neutral; the overall charge of it is equal to zero. Binary ionic compound is composed of two different ions. <u>Ca²⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds. </u>
CaS can be formed via combining Ca²⁺ with S²⁻ to form the neutral binary ionic compound CaS.CaBr₂ can be formed via combining 1 mole of Ca²⁺ with 2 moles of Br⁻ to form the neutral binary ionic compound CaBr₂.
<u>V⁵⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds. </u>
V₂S₅ can be formed via combining 2 moles of V⁵⁺ with 5 moles of S²⁻ to form the neutral binary ionic compound V₂S₅.VBr₅ can be formed via combining 1 mole of V⁵⁺ with 5 moles of Br⁻ to form the neutral binary ionic compound VBr₅.
<em>So, the empirical formula of four binary ionic compounds that could be formed is: CaS, CaBr₂, VBr₅, and V₂S₅. </em>
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F = (mass)(acceleration) = ma
m = 55 kg
Vi = 20 m/s
t = 0.5 s
Vf = 0 m/s (since she was put to rest)
a=(Vf-Vi)/t
a=(0-20)/5
a = 40 m/s^2 (decelerating)
F = ma = (55 kg)(40 m/s^2)
F = 2200 N
Answer:
You subtract the atomic number from the mass number to find the number of neutrons. If the atom is neutral, the number of electrons will be equal to the number of protons.
