A hypothesis
-Can be tested
-Is a prediction about the expected outcome of an experiment
-Must be stated in a form that can be either proven or disproven
Your answer is D: All of the above are true
Answer:
3.98×10⁻¹⁹ J
Explanation:
Applying,
E = hf................. Equation 1
Where E = energy of the photon, h = planck's constant, f = frequency of the photon
From the question,
Given: f = 6.00×10¹⁴ Hz
Constant: h = 6.626×10⁻³⁴J.s
Substitute these values into equation 1
E = (6.00×10¹⁴)(6.626×10⁻³⁴)
E = 39.756×10⁻²⁰
E = 3.98×10⁻¹⁹ J
Hence the energy of the photon in joules is 3.98×10⁻¹⁹ J
Here is the formula that will help to solve this task: <span>P1/T1 = P2/T2 </span>
<span>
Keep in mind that value 20 C is an equivalent to 293 K.
If you have to make new pressure</span><span> 12.4 atm, the given temperature must be changed intor 284K.
Therefore:
</span>The correct answer is B)At 15.4 atm, T2 would have to be 353 K (which is 120 C)
As you can see, these options are not suitable:
<span>At 16.6 atm, T2 would have to be 381 K </span>
<span>At 18.6 atm, T2 would have to be 426 K</span>
Answer:
Pressure = 47.1kPa
Explanation:
V1 = 5.0L
P1 = 94.2kPa = 94.2*10³Pa
V2 = 2V1 = 2 * 5.0 = 10L
P2 = ?
To solve this question, we'll have to use Boyle's law which states that the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant
Mathematically,
V = k/P, k = PV
P1V1 = P2V2 = P3V3=........=PnVn
P1V1 = P2V2
Solve for P2
P2 = (P1 * V1) / V2
P2 = (94.2*10³ * 5.0) / 10
P2 = 47100Pa
P2 = 47.1kPa
The new pressure of the gas is 47.1kPa
The rate determining step would be the slow step. Thus, Step 2 which is bimolecular is the rate determining step. I believe the correct answer from the choices listed above is option C. The reasonable conclusion would be that it <span> is second order overall because step 2 is bimolecular. Hope this answers the question.</span>