Answer:
2 atm
Explanation:
Chemical reactions are carried out at a certain rate. Sometimes that rate is quite slow, so we want to speed things up, which is usually used by increasing temperature, increasing pressure or adding a catalyst (a substance that increases the rate without changing itself).
If this is the case, then, when writing a chemical equation, we state these special conditions over a right arrow.
Now let's look at the answers:
- 25°C is a value and unit of temperature
- ∆ is a symbol that denotes change
- 2 atm is a value and unit of pressure (atmosphere is old unit for pressure)
- Pt is a chemical symbol for platinum, an element often used as a catalyst.
So, the correct answer is C) 2 atm
Answer:
D. MgO
Explanation:
We need to look at the charge of element. (Look at a periodic table for this)
Mg, which is Magnesium, has a charge of 2+ because it's in the second column, or group, from the left.
O, which is Oxygen, has a charge of 2- because it's in the second column, or group, from the right.
Since Mg is 2+, it's the cation and since O is 2-, it's the anion. We can put these two elements together into an ionic compound.
Mg^(2+) and O^(2-) becomes Mg2O2, where we can cancel the 2s: MgO.
Thus, the answer is D.
Hope this helps!
Answer:
[Ar] 4s2 3d10 4p3
Explanation:
Arsenic is Element 33. It is the 15th element in the Fourth Row, following the noble gas Ar at the end of the Third Row.
Thus, its noble gas electron configuration is
[Ar] 4s2 3d10 4p3
Answer:
The response can be defined as follows:
Explanation:
ATP is a hydrolysis energy-saving money of the cell. It is used to support the cell's endothermic processes.
![ATP\ +\ H_{2}O\ \rightleftharpoons \ ADP\ +\ P_{i}\\\\Q\ = \ \frac{[ADP][P_{i}]}{[ATP][H_{2}O]}\\\\ADP= 0.250 \ M\\\\P_i = 0.010 \ M\\\\ATP = 0.150 \ M\\\\H_2O = 55.55 \ M\\\\\Delta G \ =\ \Delta G^{o}\ +\ 2.303\ RT\ \log\ Q\\\\R = 8.314 \frac{J}{mol\ K}\\\\T = 298\ K\\\\](https://tex.z-dn.net/?f=ATP%5C%20%2B%5C%20H_%7B2%7DO%5C%20%5Crightleftharpoons%20%5C%20ADP%5C%20%2B%5C%20P_%7Bi%7D%5C%5C%5C%5CQ%5C%20%3D%20%5C%20%5Cfrac%7B%5BADP%5D%5BP_%7Bi%7D%5D%7D%7B%5BATP%5D%5BH_%7B2%7DO%5D%7D%5C%5C%5C%5CADP%3D%200.250%20%5C%20M%5C%5C%5C%5CP_i%20%3D%200.010%20%5C%20M%5C%5C%5C%5CATP%20%3D%200.150%20%5C%20M%5C%5C%5C%5CH_2O%20%3D%2055.55%20%5C%20M%5C%5C%5C%5C%5CDelta%20G%20%5C%20%3D%5C%20%5CDelta%20G%5E%7Bo%7D%5C%20%2B%5C%202.303%5C%20RT%5C%20%5Clog%5C%20Q%5C%5C%5C%5CR%20%3D%208.314%20%5Cfrac%7BJ%7D%7Bmol%5C%20K%7D%5C%5C%5C%5CT%20%3D%20298%5C%20%20K%5C%5C%5C%5C)
