Phytoplankton are microscopic photosynthesizing organisms that typically live in the upper layers of the ocean. What trophic lev
1 answer:
You might be interested in
This question is incomplete, the complete question is;
Consider an experimental setup with two compartments separated by a phospholipid bilayer membrane containing ion channels selectively permeable only to chloride ions. The left compartment (also called inside) contains 1 mM Cl- and the right compartment (also called outside) contains 100 mM Cl-. What will the electrical potential be when the system attains equilibrium? [ assume body temperature; log 100 = 2, log 10 = 1, log 1 = 0, log 0.1 = -1, log 0.01 = -2]
Options;
a) -62 mV
b) -124 mV
c) +62 mV
d) 0 mV
e) +124 mV
Answer:
the electrical potential be when the system attains equilibrium is –124mV
Option b) –124mV is the correct answer
Explanation:
Given the data in the question;
Two compartments are divided by lipid bilayer;
In inside compartment Cl- ion concentration- 1mM and out side of the cell concentration is 100mM
now we apply the Nernst equilibrium potential equation;
Chlorine ion valency is z = –1
So
= 62/z × log(ion outside/ ion inside) [for Cl‐ ions]
= (62 / –1) x log( 100 / 1 )
= -62 x 2 =
= –124mV
Therefore, the electrical potential be when the system attains equilibrium is –124mV
Option b) –124mV is the correct answer
Answer: 8.28g Na
Explanation: use ideal gas law
PV= nRT
Solve for moles of Cl2
n= PV/ RT
Substitute:
= 1 atm x 4.0 L / 0.08205 L.atm/ mol. K x 273 K
= 0.18 moles Cl2
Do stoichiometry to solve for m of Na
2 Na + Cl2 => 2 NaCl2
=0.18 moles Cl2 x 2 mol Na/ 1 mol Cl2 x 23g Na / 1 mol Na
= 8.28 g Na.
