Step-by-step explanation:
1 km = 1000 m
(hence the term "kilo" which means 1000).
so. he runs 1000 m at the rate of 3 minutes per km, that means 3 minutes per 1000 m.
now, we can see the solution already with our eyes.
but let's do it formally :
the rate or ratio between time and distance must be the same for the same speed.
so,
3 min / 1000 m = x min / 500 m
500 m × 3 min / 1000 m = x min
1/2 × 3 min = x min
3/2 = 1.5 min = x min
so, it takes him 1.5 minutes (90 seconds) to run 500 m.
Answer:
x>4
Step-by-step explanation:
Do 5x>24-4 subtract... the u have 5x>20 so you divide both sides by 5 and u get 4
Answer:
6xy²z^4
Step-by-step explanation:
![\sqrt[3]{216x^3y^6z^12}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E3y%5E6z%5E12%7D)
= ∛(6³)(x³)(y³)(y³)(z³)(z³)(z³)(z³) = 6x·y·y·z·z·z·z = 6xy²z^4
Answer:
1-1) A=6×5=30m² | P=6×2+5×2=12+10=22m
1-2) A=5×20=100mi² | P=5×2+20×2=10+40=50mi
2-1) A=16×6=96m² | P=16×2+6×2=32+12=44m
2-2) A=20×9=180km² | P=20×2+9×2=40+18=58km
3-1) A=14×17=238yd² | P=14×2+17×2=28+34=62yd
3-2) A=20×18=360mi² | 20×2+18×2=40+36=76mi
